how do you know if the graph is a function?
if it passes the vertical line test( a straight line that touches the graph once).
what is the first step solving a trinomial
A times b and finding variables that add to B and multiply to A times C
multiply the binomial (3x+4)(3x-4)
The difference of two squares
take the square root of the first term (3x)
take the square root out of the second term (4)
9x2-16
what shape does a parabola make
a U shape
how do you find the Dagree for a polynomial
the biggest exponent
what shape does an absolute make when graphing?
A v shape
2x^2+13x-7
AxC= -14 B=2
What is the next step
2x^2-X+14-7
multiply the binomial (5x-9)(5x+9)
the difference of two squares
take the square root of the first term(5x)
take the second term out of the second term(9)
25x2-81
what is the formula when solving a parabola
y=x2
how do you find the y-intercept from a polynomial function in ordered pairs?
It's the last number in the equation
example problem-Y=x3+7x-3
the y-intercept would be (-3,0) in ordered pairs
If the equation is lx-70l where does that move the graph to?
70 units to the right
3x2+16x+21=0
what is the answer
3x2+7x+9x+21 axc=63 b=7
x(3x+7)+3(3x+7)
3x+7=0 x+3=0
x=-7/3 x=-3
multiply the binomial (x-4)(x+4)
the difference between two squares
take the first term out of the first term(x2)
take the term out of the second term(4)
x2-16
solve x2-12=0
square roof of x2 = square root of 12
after we do that we factor out x2
find factors
x2=+or- 2 square root 3
x2=+or-2 square root 3
how do you find the # of turning points in a polynomial function
once you find the degree which is the highest exponent you subtract that from one which will be your answer
f(x)=8x2+3x-4
2-1=1 There is 1 turning point possible in the graph
solve -4=1/2 /x-3/-2
there's no solution because you an absolute value can be an answer when it's a negative
how do you solve 10x2-x-21
find factors that is equal to AxC and that goes into b
10x2-15x+14x-21
what's one factor that you can take out(5)
5x(2x-3) +7(2x-3)
2x-3=0 5x+7=0
x=3/2 x=-7/5
multiply the binomial (2x+5)(2x-5)
the difference of two squares
take the square root of the first term =2x
take the square root of the second term=5
take the first (add the second term) (the first term-5)
(2x+5)(2x-5)
4x2-25
which best describes this equation when graphing?
y=2(4+2)+1
a-v shape
b- U shape
c- S shape
The answer is b and this is because it's parabola which is a U shape
what's the formula equation for a polynomial
y=x3
solve algebraically lx-3l>1
x>4,x<2
solve x2+9x+18
what factors go into axc and b (3,68)
x2+3x+68x+18
factor out x
x(x+3) +6(x+3)
x+3=0 x+6=0
x=-3 x=-6
multiply the binomial (2x+4) (2x+4)
the difference between two squares
Take the square root out of the first term(2x)
take the square root out of the second term(4)
2x2+16
after your done graphing a parabola should you have the y intercept in ordered pairs?
yes and this is because every y intercept needs order pairs when there're points on a graph.
when graphing a polynomial will you ever find the range or domain in ordered pairs?
no and this is because when graphing you will always go up,down and going to the sides