500
Solve by substitution to find the point, and say how many solutions there are..
x2+y2=10
y=-3x+10
x^2+(-3x+10)2=10
(-3x+10)(-3x+10)= x^2+(9x)2-30x-30x+100=10
10x2-60x+90=0(divide everything by 10)
x2-6x+9=0
(x-3)(x-3)=0
x-3=0
x=3
y=-3(3)+10
y=-9+10
y=1
(3,1) one solution
x^2+(-3x+10)2=10
(-3x+10)(-3x+10)= x^2+(9x)2-30x-30x+100=10
10x2-60x+90=0(divide everything by 10)
x2-6x+9=0
(x-3)(x-3)=0
x-3=0
x=3
y=-3(3)+10
y=-9+10
y=1
(3,1) one solution