Systems Of Equation
y=2x+5 solve by substitution
3x+y=10
(1,7)
1x^0
1
5a^2+3 name the polynomial based on degree and terms
quadratic binomial
x=4y-5 solve by substitution
3x-10y=-9
(7,3)
3y^2 * 5y^8 multiply to solve
15y^10
A) 5x^2 C) 5x/3x^-4
B) -9 D) 5q^-4+6q which one is not a polynomials
D)
4x+5y=12 eliminate x to solve
-2x+y=8
(-2,4)
3x^3 * 6y^-4
18x^3/y^4
2(x^2+3x-4)
2x^2+6x-8
2x+3y=16 solve by elimination
5x-2y=21
(5,2)
5x^0
5
5n(n^2+2n)-3(n^3+2n^2)
2n^3+4n^2
4x-4y=8 solve by substitution
2x-y=1
(-1,-3)
{-27a^{3}b^{4}}/{-9a^{4}b^{4}c^{6}}
3/ac^6
2a^3b^3(4a^2b-3ab^2)+5a^3b(ab^3+4ab-6)
13a^4