Solutions to Quadratic Equations
Solving by Factoring
Writing Equations
Writing & Solving
100

What are the solutions of the equation

(x + 4)(x - 5) = 0?

{-4, 5}

100

Solve:

x2 - 7x + 12 = 0

{3, 4}

100

Write an equation to solve the following problem. DO NOT SOLVE.

The product of two consecutive odd integers is 323.

n(n+2) = 323

100

The sum of a number and its square is 56. Find the number(s).

-8 and 7

200

Solve:

(n - 9)(4n + 1) = 0

{-1/4, 9}

200

Solve:

2x2 = 8

{2, -2}

200

The altitude of a triangle is 4cm more than the base. The area is 36 cm2. Which equation best represents the situation where x represents the altitude of the triangle?

A.  x(x - 4) = 36
B.  x(x + 4) = 36
C.  x(x - 4)/2 = 36
D. x(x + 4)/2 = 36

D

200
If the length of a rectangle is six feet more than the width and the area is 112 square feet, find the width of the rectangle.

8 feet

300

If we have time:

What are the solutions?


4(x - 4)(x + 3) = 0

x = {4, -3}

300

Solve:

2c2 + 14c + 24 = 0

-3 or -4

300

If we have time: Write the equation only!

Find three consecutive positive odd integers such that the product of the first and third is equal to 1 less than twice the second.

x(x + 4) = 2(x + 2) - 1

300

If we have time: 

Find three consecutive positive odd integers such that the product of the first and third is equal to 1 less than twice the second.

1, 3, 5

400

If we have time:

What are the solutions?

3x(x - 5) = 0

x = {0, 5}

400

Solve:

12x2 - 3 = 5x

{-1/33/4}

400

If time: Write the equation only!

A rectangle has a length that is 4 meters more than the width. The area of the rectangle is 117 square meters.  

w(w + 4) = 117

400

If time only:

A rectangle has a length that is 4 meters more than the width. The area of the rectangle is 117 square meters. Find the dimensions of the rectangle.

9m by 13m

M
e
n
u