Lesson 1
Lesson 2
Lesson 3
Lesson 1
Lesson 2
100

Find the y-Intercept of y=3x-5x+7

The Y-Intercept is (0,7)

100

Given y=2(x-3)(x+5) Find the Intercepts.

Y-intercepts (0,30) X-Intercepts (3,0) and (-5,0)

100

Solve π‘₯ 2 βˆ’ 9 = 0 x 2 βˆ’9=0 using factoring.

π‘₯=3,x=3

100

A business’s profit, in thousands of dollars, is modeled by the quadratic equation: 𝑃 ( π‘₯ ) = π‘₯ 2 βˆ’ 2 π‘₯ βˆ’ 3 P(x)=x 2 βˆ’2xβˆ’3

a) Find the y-intercept of the profit function. 

b) Find the x-intercepts of the profit function.

the y-intercept is (0,βˆ’3)

The x-intercepts are (3,0) and (βˆ’1,0).

100

The path of a rocket is modeled by the equation: 

𝑦 = βˆ’ π‘₯ 2 + 4 π‘₯ βˆ’ 3 y=βˆ’x 2 +4xβˆ’3

Find the X- and Y- Intercepts.

The y-intercept is (0,βˆ’3).

The x-intercepts are (3,0) and (1,0).

200

Solve for x-Intercepts of y=x2-6x+5=0

The x-Intercepts are (5,0) and (1,0)

200

Write the factored form of a quadratic equation with x-intercepts π‘₯ = βˆ’ 1 x=βˆ’1 and π‘₯ = 4 x=4 

y=(x+1)(xβˆ’4).

200

Solve 2 π‘₯ 2 + 3 π‘₯ βˆ’ 2 = 0 2x 2 +3xβˆ’2=0

x=1/2 and x=βˆ’2

200

Find the x- and y-intercepts of 𝑦 = βˆ’ 2 π‘₯ 2 + 8 π‘₯ y=βˆ’2x 2 +8x.

X-intercepts:(0,0),(4,0)

Y-intercept:(0,0)

200

A ball is dropped and its height above the ground after t seconds is given by the equation: β„Ž ( 𝑑 ) = βˆ’ 𝑑 2 + 4 𝑑 + 5 h(t)=βˆ’t 2 +4t+5

a) Find the y-intercept of the ball's height.

b) When does the ball hit the ground?


The y-intercept is (0,5)

the ball hits the ground after 5 seconds.



300

Verify if x=2 is an X-Intercept of y=x2-4x+4

Yes x=2 in an x-Intercept

300

Find the x-intercepts of 𝑦 = 3 ( π‘₯ βˆ’ 2 ) ( π‘₯ βˆ’ 1 ) y=3(xβˆ’2)(xβˆ’1) and confirm your solution.

The x-intercepts are (2,0) and (1,0).

300

Solve π‘₯ 2 + 6 π‘₯ + 9 = 0 x 2 +6x+9=0 by completing the square.

π‘₯ = βˆ’ 3

300

The path of water in a fountain is modeled by the equation y=βˆ’x2+6xβˆ’5y = -x2 + 6x - 5y=βˆ’x2+6xβˆ’5.

a) Find the y-intercept of the fountain's path.

b) Find the x-intercepts of the fountain's path.

the y-intercept is (0,βˆ’5). 

The x-intercepts are (5,0) and (1,0).

300

y=βˆ’2(xβˆ’1)(x+4), find the x- and y-intercepts.

X-intercepts:(1,0),(βˆ’4,0)

Y-intercept:(0,8)

400

Write the equation of a parabola with a Y-Intercept of 10 and no x-intercepts

y=x2+4x+10

400

The equation of a quadratic is 𝑦 = βˆ’ 3 ( π‘₯ βˆ’ 4 ) ( π‘₯ + 2 ) y=βˆ’3(xβˆ’4)(x+2). Find the x- and y-intercepts.

X-intercepts:(4,0),(βˆ’2,0)

Y-intercept:(0,24)

400

A parabola has the equation 𝑦 = π‘₯ 2 βˆ’ 4 π‘₯ βˆ’ 5 y=x 2 βˆ’4xβˆ’5.

 a) Find the x- and y-intercepts of the parabola. 

b) Determine the x-coordinate of the vertex.


X-intercepts:(5,0) and (βˆ’1,0).

The x-coordinate of the vertex is π‘₯ = 2 x=2.

400

Find the x- and y-intercepts of 𝑦 = π‘₯ 2 βˆ’ 6 π‘₯ + 8 y=x 2 βˆ’6x+8.

X-intercepts:(4,0),(2,0)

Y-intercept:(0,8),(0,8)

400

Determine the x-intercepts and y-intercept of 𝑦 = 4 ( π‘₯ + 1 ) ( π‘₯ βˆ’ 3 ) y=4(x+1)(xβˆ’3).

X-intercepts:(βˆ’1,0),(3,0)

Y-intercept:(0,βˆ’12)

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