Finding the inverse of a function
x=-1/3y+1
y=-3x+3
x^2+9x+14
(x+2)(x+7)
Write this number in terms of i
square root -25
5i
(7+7)(i)
14i
5x^2-23=0
x=+ or - the square root of 115 divided by 5
f(x)=1/2x-5/2
g(x)=2x+5
x^2-7x-30
(x-10)(x+3)
square root -150
5i square root 6
(2+3)(3i)
15i
2(x-3)^2-5=0
x-3=+ or - the square root of 10 divided by 2
f(x)=1/8x-9/2
g(x)=8x+36
x^2-144
(x-12)(x-12)
square root -12
2i square root 3
(3i)(3i)
-9
4(x+5)^2-49=0
x1=-17/2, x2=-3/2
Is the given inverse of the equation true or false?
f(x)=x/2+3, g(x)=2x+6
False the correct inverse is g(x)=2x-6
5x^2+40x+75
5(x+5)(x+3)
square root -49
7i
(2+3i)(4-5i)
23+2i
25x^2-7=0
x=+ or - the square root of 7 divided by 5
What's the inverse of p(t)=6t+8?
p^-1(t)=t-8/6
-12x^2+108
12(x-3)(x+3)
5- square root -36
5-6i
(-5+2i)(2+-9i)
49i+8
2x^2+12x+5=0
x=-3 + or - the square root of 26 divided by 2