axis of symmetry
vertex
solutions
quadratic formula
standard to vertex form
100

y=-2(x-1)2+1

1

100

y=(x+12)2-5

(-12, -5)

100

x2+4x+3=0

Two Solutions

100

3x2+x-2=0

4/6, -1

100

y=2x2+3

y=2(x2)+3

200

y=(x-3)2+2

3

200
y=(x+4)2+3

(-4, 3)

200

2x2-4x+10=0

No Solution
200

5x2+2x-3

-1, 6/10

200

y=-2x2-12x-12

y=-2(x+3)2+6

300

y=2(x+9)2-1

-9

300

y=3(x+4)+8

(-4, 8)
300

x2-10x+25=0

One Solution
300

3x2+2x-1

-2/6, -1

300

y=x2-4x+2

y=(x-2)2-2

400

y=-2(x+4)2-6

-4

400

y=(x-5)+7

(5, 7)

400

x2+2x+1=0

One Solution

400

2x2+4x+2

-1

400

f(x)=-x2-2x-5

f(x)=-(x+1)2-4

500

y=5(x+7)2-5

-7

500

y=3(x-3)+4

(3, 4)

500

x2-2x-7=0

Two Solutions

500

8x2+4x-2

-4+-*80//16

500

f(x)=2x2+8x-7

f(x)=2(x+2)2-15

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