Solving Systems of Equations by elimination
Solving Equations by Substitution
Solve Absolute-Value Equations
Parallel and Perpendicular Lines
Solve One Step Inequalities
100
−4x − 2y = −12 4x + 8y = −24
(6,-6)
100
−2x + 6y = 6 −7x + 8y = −5
(3, 2)
100
|5x|+ 5 = 45
{8, −8}
100
through:(4,1), perpendicular to y=x+2
y=-x+3
100
x-5>-3
x>2
200
4x + 8y = 20 −4x + 2y = −30
(7,-1)
200
−3x + 3y = 3 −5x + y = 13
(−3, −2)
200
3|−8x|+ 8 = 80
{−3, 3}
200
through: (2-4)parallel to y=3x+2
y=3x-10
200
x+4<5
x<1
300
3x − 2y = 2 5x − 5y = 10
(−2, −4)
300
x + 3y = 1 −3x − 3y = −15
(7, −2)
300
5 − 8|−2n|=−75
{−5, 5}
300
through:(3,-2) perpendicular to y=5x+4
x+5y=-7
300
-8>8+y
y<-16
400
−14 = −20y − 7x 10y + 4 = 2x
(2, 0)
400
−3x − 8y = 20 −5x + y = 19
(−4, −1)
400
2 − 5 |5m − 5| = −73
{4, −2}
400
through: (2, 2), parallel to y=x+4 
y=x
400
1<s-8
s>9
500
3 + 2x − y = 0 −3 − 7y = 10x
(−1, 1)
500
−3x + 3y = 4 −x + y = 3
No solution
500
|−2n + 6| = 6
{0, 6}
500
through:(4,3),parallel to x=0
x=4
500
12<4x
x>3
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