Linear Equations
Inequalities
Foundational Skills
Factoring
Quadratics
100

Solve for p

p − 1 =5p + 3p − 8

p=1

100

solve the inequality

4/n<3

n<1.33

100

Evaluate

3(6+7)

39

100

Find the GCF of the following numbers

12, 36, 60, 24

6

100

Write m^2 as a multiplication problem.

m^2=m x m

200

solve for a
 u=ak/b

a=ub/k

200

solve the inequality

18>5k+4k

2>k

200

Evaluate

20 / (6-2(10-8))

10

200

Factor the expression by identifying the
GCF.
3g^3h - 9g^2h + 12h

3h(g3 – 3g2 + 4)

200

Which of the following is a factor of
x^2 + 15x + 54?

A. (x + 6)
B. (x + 7)
C. (x + 2)
D. (x + 3)

300

Solve the system.

2x – 3y = 4
-4x + 5y = -8

Solution: (2, 0)

300

-138> -6(6b-7)

5<b

300

Simplify

−2x + 11 + 6x

11+4x

300

Factor the difference of squares.

4x2 – 9y6

(2x + 3y^3)(2x – 3y^3)

300

Factor the expression

 x^2 + 5x + 6.

(x+3) (x+2)

400

Solve the system 


{x –(1/2)y = 1
2x + 3y = 10




solution (2,2)

400

Solstice needs $229 to buy a new laptop.
Her job pays $13 an hour, and she has $60 saved
already. What is the minimum number of hours
Solstice must work to purchase the laptop?

She has to work at least 13 hours

400

Simplify

−9(6m − 3) +6(1 + 4m)
 

-30m+33

400

Factor each binomial completely.
a) 16h^2 – 36k^2

(4h + 6k)(4h – 6k)

400

 
 solve the quadratic 
 
 
n^2 + 7n + 15 = 5

{-5,-2}

500

Your Geometry test has 29 questions. Each
question is either worth 2 points or 5 points, and
all together the test is out of 100 points. How
many 2-point questions are there?

x=15    y=14

500

The Clinton High School art club sells
candles for a fundraiser. The first week of the
fundraiser, the club sells 7 cases of candles. Each
case contains 40 candles. The goal is to sell at
least 13 cases. During the second week of the
fundraiser, the club meets its goal. Write, solve,
 an inequality that can be used to find
the possible number of candles sold the second
week.

n ≥ 240
The art club sells at least 240 candles.

500

Solve inequality

3< p/2<0

-6<p<0

500

Factor the expression (a – 3b)^2 – 225.

(a – 3b + 15)(a – 3b – 15)

500

Solve the binomial

 
 
(2m + 3)(4m + 3) = 0
 

{-3/2, 3/4}

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