Equations
9 = m + 49
9 = m + 49
m = −40
((−7) + (−9) − 8) ÷ (−8)
((−7) + (−9) − 8) ÷ (−8) = ((−16) − 8) ÷ (−8)
= (−24) ÷ (−8) =3
16× 5 =
32- 15 =
19× 15 =
15× 17 =
13+ 6 =
16× 5 =80
32- 15 =17
19× 15 = 285
15× 17 = 255
13+ 6 =19
3/5 : 9/10 =
2/4 x 4/15 =
2/4 + 2/19 =
3/5 : 9/10 = 2/3
2/4 x 4/15 = 2/15
2/4 + 2/19 = 23/38
Before Cam broke his right arm, he was able to type 9 words per minute on his phone. After he broke his arm, he had to use his left hand for a while, and he could only type 6 words per minute. What is the difference between the number of words he could type in 5 minutes before and after he broke his arm.
Before Cam broke his right arm, he was able to type 9 words per minute on his phone. After he broke his arm, he had to use his left hand for a while, and he could only type 6 words per minute. What is the difference between the number of words he could type in 5 minutes before and after he broke his arm.
9 words per minute x 5 minutes = 45 words; 6 words per minute x 5 minutes = 30 words; 45 words – 30 words = 15 words difference
−88 = −150 − x
−88 = −150 − x
x = −62
(−10) × (8 − 3) ÷ (−2)
(−10) × (8 − 3) ÷ (−2) = (−10) × 5 ÷ (−2)
= (−50) ÷ (−2)
= 25
9-1=
20× 1 =
133÷7=
20+ 3 =
192÷12=
9-1=8
20× 1 =20
133÷7=19
20+ 3 =23
192÷12=16
2/3 - 2/8 =
4/7 + 2/16 =
2/6 - 1/5 =
4/10 : 1/2 =
4/7 - 2/6 =
2/3 - 2/8 = 5/12
4/7 + 2/16 = 39/56
2/6 - 1/5 = 2/15
4/10 : 1/2 = 4/5
4/7 - 2/6 = 5/21
What is 51% of 200?
What is 71% of 1,000?
What is 13% of 100?
What is 9% of 200?
What is 17% of 600?
What is 51% of 200? 102
What is 71% of 1,000? 710
What is 13% of 100? 13
What is 9% of 200? 18
What is 17% of 600? 102
118−p = 60
118−p = 60
p=58
((−8) + 2) × (5 ÷ (−5))
((−8) + 2) × (5 ÷ (−5)) = (−6) × (5 ÷ (−5))
= (−6) × (−1) =6
348 − 199 =
595 + 215 =
966 - 246 =
457 - 309 =
985 + 606 =
348 − 199 = 149
595 + 215 = 810
966 - 246 = 720
457 - 309 = 148
985 + 606 = 1591
4.188698 ÷ 6.001 =
0.22 ÷ 0.044 =
7.15312 ÷ 0.247 =
0.5307 ÷ 6.1 =
0.062328 ÷ 0.742 =
4.188698 ÷ 6.001 = 0.698
0.22 ÷ 0.044 = 5
7.15312 ÷ 0.247 = 28.96
0.5307 ÷ 6.1 = 0.087
0.062328 ÷ 0.742 = 0.084
In Science class, Sara needed 8 test tubes for 3 different experiments. The first experiment required 2 test tubes and the other two experiments required the same number of test tubes. How many test tubes were needed for each of the other two experiments?
In Science class, Sara needed 8 test tubes for 3 different experiments. The first experiment required 2 test tubes and the other two experiments required the same number of test tubes. How many test tubes were needed for each of the other two experiments?
8 test tubes – 2 test tubes = 6 test tubes; 6 test tubes divided by 2 = 3 test tubes for each of the other experiments
3c−6=21
3c−6=21
c=9
(6 − (−8) + 10) × 3
(6 − (−8) + 10) × 3 = (14 + 10) × 3 = 24 × 3 =
= 72
435 x 72 =
325 x 54 =
804 x 79 =
908 x 47 =
905 x 0 =
435 x 72 = 31 320
325 x 54 = 17 550
804 x 79 = 63 516
908 x 47 = 42 676
905 x 0 = 0
44.99 × 55.5 =
30.9 × 0.2 =
9419.4 × 6.1 =
9.92 × 4621.6 =
669.2 × 0.49 =
44.99 × 55.5 = 2496.945
30.9 × 0.2 = 6.18
9419.4 × 6.1 = 57458.34
9.92 × 4621.6 = 45846.272
669.2 × 0.49 = 327.908
Start Date is Aug 23, 2006
Elapsed Time is 9 years 4 months 3 weeks 4 days
WHAT IS End Date?
Start Date is Aug 23, 2006
Elapsed Time is 9 years 4 months 3 weeks 4 days
End Date is Jan 17, 2016
7z=63
7z=63
z=9
2×(3^3 −5+8)
2×(3^3 −5+8)
= 2 × (27 − 5 + 8) = 2 × (22 + 8)
= 2 × 30
= 60
536 : 36 =
825 : 43 =
912 : 22 =
71070 : 690 =
5208 : 7 =
1872 : 4 =
2853 : 9 =
6300 : 7 =
536 : 36 = 14 r 32
825 : 43 = 19 r 8
912 : 22 = 41 r 10
71070 : 690 = 103
5208 : 7 = 744
1872 : 4 = 468
2853 : 9 = 317
6300 : 7 = 900
134.5 + 426.2 =
60.04 + 589.95 =
510.70 + 0.065 =
54.11 −0.3 =
29.40 −0.183 =
134.5 + 426.2 = 560 .7
60.04 + 589.95 = 649 .99
510.70 + 0.065 = 510 .765
54.11 −0.3 = 53.81
29.40 −0.183 = 29.217
Round each Euro amount to the nearest 10 cents. The ≈ sign means approximately equal to.
e8.66 ≈
e8.82 ≈
e3.24 ≈
e9.16 ≈
e2.24 ≈
Round each Euro amount to the nearest 10 cents. The ≈ sign means approximately equal to.
e8.66 ≈ e8.70
e8.82 ≈ e8.80
e3.24 ≈ e3.20
e9.16 ≈ e9.20
e2.24 ≈ e2.20