Simplify Radicals
√63
3√7
5+14a=9a-5
a=-2
5x^2+70x+245=0
x=-7
x^4-y^3+4xy^2
4
(x+3)^2 + (y+2)^2 = 9
What is the radius?
3
√52x^4
2x^2√13
3(6-f)-4=3f-4
f=3
2x^2-40x+200=0
x=10
3xy-4x^7+2x^3
7
(x-5)^2 + (y+3)^2 = 36
What is the center?
x=5
y=-3
√112a^6
4a^3√7
20-6+4k=2-2k
k=-2
9+7x=7x^2
-7+-√301/-14
ab^2+a^2b^3-a^3b^1
5
(x+2)^2 + (y+4)^2 = 4^2
What is the center and radius?
Center: (-2,-4)
Radius: 4
2√7x * 3√14x^2
42x√2x
7(y-3)=2(y-9)+2y
y=1
f(x)=x^2-6x+43
(x+-3)^2+34
6x^5+5x^4-3x^2+x^7
7
Given that x=5 and y=-6, and the radius is 8^2, write the equation of a circle in standard form.
(x-5)^2 + (y+6)^2 = 8^2
√72x^3z^3
6xz√2xz
5(3x+2)-2=-2(1-7x)
x=-10
3x-9x^2=-10
-1+-√41/-6
12x^2y^3+6xy^4z-2xz+1
6
x^2+y^2-8x+7=0
(x-4)^2 + y^2=9