Middle School Math Olympics - PEMDAS & Finding X

PEMDAS

100

(40+14)÷6 =

9

200

40×(14−6) =

320

300

35+6×(30−23) =

77

400

(19+2)÷(9−2)+14 =

17

500

(34−26)×3−(20−8)÷6+33 =

55

Finding X (Easy Mode) 1

100

w – 1   =   6

w = 7

200

v – 8   =   7

v = 15

300

5   =   12x

x = 5/12

400

10 + 9   =   3p

p = 6 1/3 or 19/3

500

2 · 9   =   8 + w

w = 10

Finding X (Easy Mode) 2

100

1 + w   =   3

w = 2

200

9x   =   8

x = 8/9

300

3   =  z/12

z = 36

400

w/9   =   8 - 9

w = 9

500

x/7 = 12

x = 84

Finding X 2 (Hard Mode) 1

100

9(k – 4)   =   4 · 3

k = 5 1/3 or 15/3

200

3(b + 4) + 8   =   –3

b = -7 2/3 or -23/3

300

–3   =   7p – 5

p = 2/7

400

2   =   3 – 2t

t = 1/2

500

–1 – 4s   =   8

s = -2 1/4 or -9/4

Finding X 2 (Hard Mode) 2

100

–5 – v / 3  =  1

v = -8

200

7(x + 6) + 7x   =   9

x = -2 5/14 or -33/14

300

–3(–4 – b)   =   5  –  8b / 4

b = -1 2/5 or -7/5

400

8(t + 5) + 2   =   4.8t + 4

t = -11.875

500

2(a – 8.5) – 2.6   =   3.1a + 7.4

a = -24.545