Keq
Delta G standard
redox reactions
reduction potentials
more voltage/mix
100

Calculate the value of [N2]eq if [H2] =0.2M, [NH3] = 0.5M and Kc= 2

N2 (g) + 3H2 -> 2NH3 

0.016M
100

Why can't we say that a spontaneous reaction is a fast reaction?

The speed of a reaction is not related to the spontaneity. A spontaneous reaction can
be very slow.


100

balance: acidic cond

 H3PO2 + Cr2O72- → H3PO4 + Cr3

16H+ + 3H3PO2 + 2Cr2 O72- → 3H3PO4 + 4Cr3+ + 8H2O

100

Based on the following information,
Cl2(g) + 2 e- → 2 Cl-(aq) E° = +1.36 V
Mg2+(aq) + 2 e- → 2 Mg(s) E° = -2.37 V
Identify the strongest reducing agent?

Mg (s) because when it is a reducing agent it has the highest E cell. 

100

A voltaic cell has a standard cell potential equal to 0.74 V. If the standard reduction potential for the anode is -.22V what is the standard electrode potential for the cathode?

0.52V

200

Which of the following statements is TRUE?
A) If Q < Keq, it means the reverse reaction will proceed to form more reactants.
B) If Q > Keq, it means the forward reaction will proceed to form more products.
C) If Q = Keq, it means the reaction is at equilibrium.
D) All of the above are true.
E) None of the above are true

C

200

Choose the statement below that is TRUE.
A) Keq > 1, ΔG°rxn is positive.
B) Keq < 1, ΔG°rxn is negative.
C) ΔG°rxn = 0 at equilibrium.
D) ΔGrxn = 0 at equilibrium.
E) None of the above statements are true.

D

200

What is the difference between balancing redox reactions in acidic and basic solutions

Basic solutions will add an equivalent # of H+ using OH- to both sides. Then each H+ and OH- will make H2O

200

The cell notation Al(s)/Al3+(aq)//Co2+(aq)/Co(s) indicates that, 

A) Co(s) oxidizes

B) Co2+ oxidizes

C) Al(s) oxidizes 

D) Al3+ reduces

E) Al(s) reduces

Al(s) oxidizes

200

Will this reaction be spontaneous?

Ag(s)+Fe3+(aq)→Ag+(aq)+Fe2+(aq)\text{Ag(s)} + \text{Fe}^{3+}(aq) \rightarrow \text{Ag}^{+}(aq) + \text{Fe}^{2+}(aq)Ag(s)+Fe3+(aq)→Ag+(aq)+Fe2+(aq)

Given:

  • Fe³⁺ + e⁻ → Fe²⁺ E° = +0.77 V

  • Ag⁺ + e⁻ → Ag(s) E° = +0.80 V

E is negative so no

300

Determine the value of Kc for the following reaction if the equilibrium concentrations are as
follows: [HCl]eq = 0.13 M, [HI]eq = 5.6 × 10-16 M, [Cl2]eq = 0.0019 M.
2 HI(g) + Cl2(g) ⇌ 2 HCl(g) + I2(s)


2.8 × 10^31


300

What is true if ln(Keq) is negative?
A) ΔGorxn is positive and the reaction is product favored.
B) ΔGorxn is negative and the reaction is product favored.
C) ΔGorxn is negative and the reaction is reactant favored.
D) ΔGorxn is positive and the reaction is reactant favored.
E) ΔGorxn is zero and the reaction is at equilibrium.

d

300

Predict the species that will be reduced first
Zn2+, Fe3+, Mg2+, Br-, I-
A) Zn2+ B) Mg2+ C) Br- D) Fe3+ E) I-

D) Fe3+ because it has the highest E cell. 

300

What is the balanced chemical equation for the galvanic cell reaction expressed using shorthand
notation below?
Al(s) ∣ Al3+(aq) ∣∣ Fe2+(aq) ∣ Fe(s)

2 Al(s) + 3 Fe2+(aq) → 2 Al3+(aq) + 3 Fe(s)

300

Will this reaction occur spontaneously?

Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s)\text{Zn(s)} + \text{Cu}^{2+}(aq) \rightarrow \text{Zn}^{2+}(aq) + \text{Cu(s)}Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s)

Given:

  • Cu²⁺ + 2e⁻ → Cu(s)  E° = +0.34 V

  • Zn²⁺ + 2e⁻ → Zn(s)  E° = –0.76 V

Yes E=1.10V

400

The equilibrium constant Kc fro the following reaction is known to be 0.141 at 25 C. 

2BrCl(g) -> BR2(g) + Cl2(g)

If the initial concentrations of Br2 and Cl2 are 0.1M and the initial concentration of BrCl is 0.2M what are the equilibrium concentrations of all species?

Br2 and Cl2 is 0.0858M

BrCl + 0.228M

400

Use the free energies of formation given below to calculate the equilibrium constant (Keq) for the
following reaction at 298 K.
2 HNO3(aq) + NO(g) → 3 NO2(g) + H2O(l) K = ?
ΔG°f (kJ/mol) -110.9 87.6 51.3 -237.1

1.15 x 10^-9

400

What is the value of the equilibrium constant for the redox reaction below at 25C that happens in acidic conditions? 

MnO4-(aq) + Pb2+(aq) <-> Mn2+(aq) + PbO2(s)

286,051 KJ

400

A voltaic cell consists of a peice of Mn (s) immersed in Mn2+(aq) electrode (E= -1.18V) and a piece of Fe(s) immersed in Fe2+ electrode (E=-.44V). Calculate Fe2+ concentration if [Mn2+] is 0.05M and E cell is .78V at 25c. 

1.127M

400

The standard voltage output for the cell using the overall cell reaction below is +.48V: 

Zn (s) + Ni2+(aq) -> Zn2+(aq) + Ni (s)

The voltage generated by the cell when [Ni2+]= 2.5M and [Zn2+] = .100M

0.52

500


Consider the equilibrium: 2ICl(g) = I2 (g) + Cl2 (g) Keq= 10.0
If x moles of ICl were placed in a 5.0 L container at 10 oC and if an equilibrium concentration of I2 was found to be 0.60 M, calculate the
number of moles ICl initially present

6.9 mols

500

See powerpoint


blebleh

500

Determine the rate law and the value of k for the following reaction using the data provided.
NO2(g) + O3(g) → NO3(g) + O2(g)

[NO2]i [O3]i [initial rate]
0.10   0.33   1.42
0.10   0.66   2.84
0.25   0.66   7.10


43 M-1s-1[NO2][O3]

500

Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction
occurring in an electrochemical cell at 25°C. (The equation is balanced.)
Pb(s) + Br2(l) → Pb2+(aq) + 2 Br⁻(aq)
Pb2+(aq) + 2 e⁻ → Pb(s) E° = -0.13 V
Br2(l) + 2 e⁻ → 2 Br⁻(aq) E° = +1.07 V

A

500

Which half reactions have the strongest reducing agent among the following species? 

Co2+ + 2e- <-> Co(s) Ecell = -0.28 V

Fe2+(aq) + 2e- <-> Fe (s) Ecell = -0.45 V

Cr2+ (aq) + 2e- <-> Cr (s) Ecell = -0.92 V

Sr2+ (aq) + 2e- <-> Sr (s) Ecell = -2.89 V

A) Co(s) B)Co2+ C) Sr(s) D) Sr2+ 

C) Sr(s)

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