Acids, Bases & Strength
Calculate That pH!
Buffers
Titration Solution
Redox
100

In NH₃ + H₂O ⇌ NH₄⁺ + OH⁻, identify the Brønsted–Lowry acid and base, and both conjugate pairs.

H₂O is the acid; NH₃ is the base. Conjugate pairs: NH₄⁺/NH₃ and H₂O/OH⁻.

100

Calculate the pH and pOH of 0.0200 M KOH.


pOH = −log(0.0200) = 1.699. pH = 12.301.

100

Which pair forms a buffer: HNO₃/KNO₃, HCN/KCN, or NaOH/NaCl? Explain.


HCN/KCN, because it supplies a weak acid and its conjugate base.

100

At equivalence, is the solution acidic, basic, or neutral for each titration?

  1. HCl with NaOH
  2. CH₃COOH with NaOH
  3. NH₃ with HCl
  • Neutral: strong acid–strong base.  
  • Basic: acetate reacts with water to produce OH⁻.  
  • Acidic: ammonium reacts with water to produce H₃O⁺.
100

Which process loses electrons? Which gains electrons? Is the oxidizing agent oxidized or reduced?

Oxidation loses electrons; reduction gains electrons. The oxidizing agent is reduced.

200

H₂PO₄⁻ can either gain or lose a proton. Write its conjugate acid and conjugate base. What term describes this ability?

Conjugate acid: H₃PO₄. Conjugate base: HPO₄²⁻. H₂PO₄⁻ is amphiprotic.

200

Calculate the pH of 0.0040 M Sr(OH)₂. Assume complete dissolution.

[OH⁻] = 0.0080 M. pOH = 2.10, so pH = 11.90.

200

KNO₂ is added to an HNO₂ solution. What happens to HNO₂ ionization, [H⁺], and pH?

Added NO₂⁻ shifts HNO₂ ⇌ H⁺ + NO₂⁻ left. Ionization decreases, [H⁺] decreases, and pH increases.

200

A 20.0 mL sample of 0.150 M weak base is titrated with 0.100 M HCl. What HCl volume reaches equivalence? What is the total solution volume at half-equivalence?


 Initial base = 0.00300 mol. Equivalence requires 30.0 mL HCl. Half-equivalence requires 15.0 mL HCl, giving 35.0 mL total volume.

200

Find the oxidation number of:

  1. Cl in NaClO
  2. N in NO₃⁻
  3. O in H₂O₂


Cl = +1; N = +5; O = −1.

300

Which acid is stronger in each pair? Explain why.

  1. HCl or HBr
  2. HOBr or HOCl
  3. HClO₂ or HClO₃
  • HBr: weaker H–Br bond.  
  • HOCl: chlorine is more electronegative.  
  • HClO₃: additional oxygen stabilizes the conjugate base.
300

Is 0.100 M NaCH₃COO acidic or basic? Calculate its pH. Kₐ(CH₃COOH) = 1.8 × 10⁻⁵.

Basic. pH = 8.87.

300

Mix 30.0 mL of 0.100 M NH₄Cl with 10.0 mL of 0.100 M NaOH. Does a buffer form? Give the final moles of NH₄⁺ and NH₃.

OH⁻ + NH₄⁺ → NH₃ + H₂O. Initially: 3.00 mmol NH₄⁺ and 1.00 mmol OH⁻. Finally: 2.00 mmol NH₄⁺ and 1.00 mmol NH₃. A buffer forms.

300

Methyl orange has a red protonated form and a yellow deprotonated form. Which form dominates well below its pKₐ? At pH = pKₐ, what is the ratio of the two forms?

The red, protonated form dominates below pKₐ. At pH = pKₐ, the protonated and deprotonated forms have equal concentrations: 1:1.

300

For Zn + 2Ag⁺ → Zn²⁺ + 2Ag, identify the species oxidized, species reduced, oxidizing agent, and reducing agent.

Zn is oxidized and is the reducing agent. Ag⁺ is reduced and is the oxidizing agent.


400

Arrange equal-concentration solutions of HNO₃, HClO, NH₃, KOH, and Ba(OH)₂ by increasing pH. Assume complete dissolution.

HNO₃ < HClO < NH₃ < KOH < Ba(OH)₂. Ba(OH)₂ supplies two OH⁻ per formula unit.

400

Calculate the pH and percent ionization of 0.100 M HA with Kₐ = 1.0 × 10⁻³. Check the small-x approximation.

The approximation predicts 10% ionization, so it fails the 5% check. Solve x²/(0.100 − x) = 0.00100. [H⁺] = 0.00951 M. pH = 2.02; ionization = 9.51%.

400

A buffer contains 0.100 mol CH₃COOH and 0.100 mol CH₃COO⁻. Calculate its pH after adding 0.0200 mol HCl. Kₐ = 1.8 × 10⁻⁵. Assume negligible volume change.


HCl converts acetate into acetic acid. Final amounts: 0.0800 mol acetate and 0.120 mol acid. pH = 4.745 + log(0.0800/0.120) = 4.57.

400

A 25.0 mL sample of 0.100 M HCOOH is titrated with 0.100 M NaOH. Calculate the pH after adding 10.0 mL NaOH. Kₐ(HCOOH) = 1.8 × 10⁻⁴.

Initially 2.50 mmol acid. Added OH⁻ = 1.00 mmol. Finally: 1.50 mmol HCOOH and 1.00 mmol HCOO⁻. pH = 3.745 + log(1.00/1.50) = 3.57.

400

Write the balanced half-reaction for NO₃⁻ being reduced to NO in acidic solution.

NO₃⁻ + 4H⁺ + 3e⁻ → NO + 2H₂O.

500

For a triprotic acid, rank Kₐ₁, Kₐ₂, and Kₐ₃, then rank their pKₐ values. During titration with a strong base, where does pH equal each pKₐ?


Kₐ₁ > Kₐ₂ > Kₐ₃; pKₐ₁ < pKₐ₂ < pKₐ₃. The pH equals each pKₐ at its corresponding half-equivalence point, halfway through that proton’s neutralization.

500

Calculate the pH of a 0.200 M NH₄Cl solution at 25°C. Is the solution acidic, basic, or neutral?

Given: Kᵦ(NH₃) = 1.8 × 10⁻⁵.

NH₄⁺ is a weak acid; Cl⁻ is neutral. 


ph= 4.98

500

Two 1.00 L buffers have equal acid-to-conjugate-base ratios. Buffer A contains 0.010 mol of each component; Buffer B contains 0.100 mol of each. Compare their initial pH values and their resistance to added HCl.

Their initial pH values are approximately equal, because their ratios are equal. Buffer B has greater capacity and experiences a smaller pH change for the same HCl addition.

500

A 20.0 mL sample of 0.150 M weak base B is titrated with 0.100 M HCl. Kᵦ(B) = 1.0 × 10⁻⁵. Calculate the pH:

  1. At equivalence
  2. After adding 40.0 mL HCl


  • At equivalence: 0.00300 mol BH⁺ in 0.0500 L, so [BH⁺] = 0.0600 M. Kₐ = 1.0 × 10⁻⁹. [H⁺] ≈ √(KₐC), giving pH = 5.11.  
  • Excess HCl = 0.00400 − 0.00300 = 0.00100 mol in 0.0600 L. [H⁺] = 0.0167 M, giving pH = 1.78
500

Balance the following reaction in basic solution and identify the oxidizing agent:

Cr(OH)₃ + ClO⁻ → CrO₄²⁻ + Cl⁻

2Cr(OH)₃ + 3ClO⁻ + 4OH⁻ → 2CrO₄²⁻ + 3Cl⁻ + 5H₂O.

ClO⁻ is the oxidizing agent: chlorine is reduced from +1 to −1.



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