Linear
6y−5=−3(2y+1)
y= 1/6
|8 + p| = 2p – 3
p=11 and p=-5/3
3a + 7 ≤ 16
a </= 3
Write in standard form
8x + 3y + 6 = 0
8x+3y=-6
Solve using substitution
3x + y = 7
4x + 2y = 16
x=-1
y=10
Solve 8(2x – 3) – 4(x + 5) = 10.
x = _______
x= 3.2
5 – 3|2 + 2w| = –7
w=1 and w=-3
Solve –3(x + 7) ≤ –15
x ≥ –2
write in slope-intercept form
6x + 3y = 12
y= -2x+4
Solve using elimination
3x ‒ 2y = 4
5x + 3y = ‒25
x=-2
y=-5
find the related function and graph
‒x + 3 = 6
x= -3
|3n – 2| – 2 < 1
n<5/3 and n>-1/3
(4x-3)/2 > 3.5
x > 2.5
Put in point-slope form
slope of ‒5, passes through (‒3, ‒8)
y+8=-5(x+3)
Create the system then solve
The sum of two numbers is 12. The difference of the same two numbers is ‒4. Find the
two numbers.
x=4 y=8
The height h of a falling object is given by h=vt-gt2, where v is the initial velocity of the object, t is time, and g is the gravitational constant. Solve for v.
v=
v=h+gt2/t
‒3y ‒ 2 ≤ |6y + 25|
y >/= -3 and y </= -3/23
3|2z ‒ 4| ‒ 6 > 12
z>5 and z<-1
Write in standard form
4/5y + 1/8x = 4
5x + 32y = 160
Solve and graph
x – y ≤ 2
x + 2y ≥ 1
y >/= x-2
y>/= -1/2x +1/2
REASONING The length of a rectangle is twice the width. Find the width if the perimeter is 60 centimeters. Define a variable, write an equation, and solve the problem
w = width
2w = length
w + 2w= 60
w=20
Write an absolute value equation to represent each situation. Then solve the equation
-The absolute value of the sum of 4 times a number and 7 is the sum of 2 times a number and 3.
x=5 and x= -5/3
Ana and Ling are solving |3x + 14| = ‒6x. Is either of them correct? Explain your reasoning.
Ana: Ling:
3x+14=-6x or 3x+14=6x 3x+14=-6x or 3x+14=6x
9x=-14 14=3x 9x=-14 14=3x
x=-14/9 x=14/3 x=-14/9 x=14/3
Both are correct
Put in point-slope form
(‒2, ‒4) and (1, 8)
y+4=3(x+2)
or
y - 8=3(x-1)
Find the solution(s)
2p – q + 4r = 11
p + 2q – 6r = –11
3p – 2q –10r = 11
(2, -5, 0.5)