Definitions/Formulas
z-scores
Area under the curve
Sample Distributions
Approximating Binomial Distributions
100

For a standard normal curve, μ = ___ and σ = ___.

μ = 0, σ = 1

100

If given x, μ, and σ, how do we calculate z?

z = (x - μ)/σ

100

Given μ = 493 and σ = 111, find P(x < 600).

P(x < 600) = 0.8325
100

The amounts of time employees at a large corporation work each day are normally distributed, with a mean of 7.6 hours and a standard deviation of 0.35 hour. Random samples of size 12 are drawn from the population and the mean of each sample is determined. What is the standard deviation of the sample?

0.1010

100

If n = 50 and p = .65, find μ and σ

μ = 32.5, σ = 3.3727

200

For a sample distribution, μx = ___ and σx = ___.

μ, σ/sqrt(n)

200

Find z when x = 49, μ = 58, and σ = 9

z = -1

200

Given μ = 12 and σ = 0.2, find P(x > 11.9).

P(x > 11,9) = 0.6915

200

If μ = 64.3, σ = 2.6, and n = 60, find P(x > 66)

P(x > 66) = 2.0490 x 10-7
200

Write the normal probability P(150 < x < 200) as a binomial probability.

P(150.5 < x < 199.5)

300

When using a normal curve to approximate a binomial distribution, what conditions must be met?

np ≥ 5

nq ≥ 5

300

Find z when x = 110.37, μ = 96, and σ =21

z = 0.6838

300

Given μ = 0.425 and σ = 0.005, find P(0.40 < x < 0.42).

P(0.40 < x < 0.42) = 0.1587

300

The population mean annual salary for environmental compliance specialists is about $63,500. A random sample of 35 specialists is drawn from this population. What is the probability that the mean salary of the sample is less than $60,000? Assume σ = $6100

P(x < 60000) = 0.2831

300

Sixty-two percent of adults in the United States have an HDTV in their home. You randomly select 45 adults in the United States and ask them if they have an HDTV in their home. Find the mean and standard deviation.

μ = 27.9, σ = 3.2561

400

Q3 = ___

0.75 or 75%

400

Find z when p = 0.42

z = -0.2019

400

Given μ = 0.5 and σ = 0.008, find x when P = 0.16

x = 0.4920

400

The mean critical reading SAT score is 501, with a standard deviation of 112. A particular high school claims that its students have unusually high critical reading SAT scores. A random sample of 50 students from this school was selected, and the mean critical reading SAT score was 515. Find the probability of a school having a mean score of 515 or higher and determine if the high school is justified in its claim.

P(x ≥ 515) = 0.1884; The school is not justified in its claim.

400

Five percent of adults in the United States are planning to purchase a 3D TV in the next two years. You randomly select 95 adults in the United States and ask them if they are planning to purchase a 3D TV in the next two years. Can we use a normal distribution to approximate this binomial distribution?

No, np = 4.75

500

D2 = ___

0.20 or 20%

500

Find z for D8

z = 0.8416

500

Given that the average SAT score is 493 and the standard deviation is 111, if 1000 SAT writing scores are randomly selected, about how many would you expect to be greater than 650?

79 scores

500

A machine in a manufacturing plant is calibrated to produce a bolt that has a mean diameter of 4 inches and a standard deviation of 0.25 inch. An engineer takes a random sample of 25 bolts from this machine and finds the mean diameter is 4.2 inches. What conclusions can the engineer make from his findings?

No conclusions can be made, as n < 30

500

A drug manufacturer claims that a drug cures a rare skin disease 75% of the time. The claim is checked by testing the drug on 100 patients. If at least 70 patients are cured, this claim will be accepted. Find the probability that the claim will be rejected assuming that the manufacturer’s claim is true.

1 - P(x > 69.5) = 0.1020

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