Nucleic Acid Structure
Prokaryotic Initiation
Eukaryotic Initiation
Elongation
Termination
100

If adenine is 15%, thymine is...

15%

100

Replication begins at this location in the DNA.

Origin of replication

100

Unlike bacteria, eukaryotes have multiple of these sites.

origins of replication

100

New nucleotides on the daughter strand are assembled in this direction.

5' to 3'

100

This polymerase in bacteria is required to remove and replace the RNA primers.

DNA polymerase I

200

RNA has this nitrogen base that DNA does not have.

Uracil

200

These proteins recognize consensus sequences in the DnaA boxes.

DnaA proteins

200

Unlike bacteria, the chromosomes of eukaryotes are this shape.

Linear

200

Replication on the leading strand is continuous, whereas replication on the lagging strand is...

Discontinuous

200

Flap endonuclease performs this function in eukaryotes.

remove the RNA primer only

300

The part of the double helix where proteins will bind.

Major groove

300

Once the DNA helix is unwound, replication will proceed in this direction.

5' to 3'

300

The ORC is required for this step of eukaryotic replication.

initiation

300

DNA replication on the leading strand is accomplished by this DNA polymerase in eukaryotes.

DNA polymerase epsilon
300

This protein must recognize the ter sequence to stop the movement of the replication fork.

Tus (termination utilization substance)

400

This scientist used X-Ray diffraction to analyze the structure of DNA.

Rosalind Franklin

400

This enzyme is the first to function in the initiation complex.

Helicase

400

This enzyme, in conjunction with primase, begins the initial replication.

DNA polymerase alpha
400

When mismatched base pairs occur on the daughter strand, this enzyme can repair them.

3' to 5' exonuclease

400

This enzyme is needed to separate the two circular DNA chromosomes in bacteria.

DNA gyrase

500

This alternative form of DNA may have implications in transcription in yeast.

Z-DNA

500

Initial separation of the double helix occurs in this region of the initiation complex of DNA.

AT-rich region

500

If MCM helicase is nonfunctional, this will be the consequence.

The DNA cannot unwind, and replication will not occur.

500

This subunit operates as a clamp to prevent DNA pol III from falling off the template strand.

beta subunit

500

A mutation in the telomerase enzyme, preventing its function, would have this consequence.

Chromosomes would get shorter with each round of replication.

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