Field Axioms
Field or No Field?
Set Closures
100

Name the property/axiom:

In any field, a + b = b + a and a x b = b x a.

The Commutative Property/Axiom

100

Name 4 of the 8 conditions we check to determine whether a set is a field.

Additive Inverse, Additive Identity, Multiplicative Inverse, Multiplicative Identity, Closure Under Addition/Multiplication, Commutative Property, Associative Property, Distributive Property


Any combination of these 8 is correct.

100

Name the four binary operations and circle the two we use to check for closure regarding fields.


Addition, Subtraction, Multiplication, and Division

200

Name the property/axiom:

The property stating that a x (b + c) = a x b + a x c.

The Distributive Property/Axiom

200

Give me a reason why the set of Whole Numbers is not a field.

No additive inverse.

or

No multiplicative inverse.

200

Name a binary operation that the set of natural numbers is NOT closed under.

Subtraction 

or 

Division

300

For addition, this element acts as the additive identity in every field.

0

300

Give me 3 reasons why the set of Irrational numbers is not a field.

No additive inverse/idenity.

No multiplicative inverse/idenity.

Not closed under addition or multiplication.

300

Name the binary operation that the set of Integers is not closed under.

Division

1/2 is not an element of the set of Integers.

400

Name the property/axiom:

The property where (a + b) + c = a + (b + c)

The Associative Property

400

Give me THE reason why the set of Integers is not a field.

It does not have the multiplicative inverse.

400

The set of odd integers is closed under multiplication (e.g., 3 x 5 = 15). Is the set of odd integers closed under addition?

(Answer is cannot be stolen)

False.


3+5 = 8

500

What is the multiplicative inverse for every element a in a field?

a-1 or 1/a

500

Set A = {-2, -1, -1/2, 0, 1, 1/2, 2}.

What axiom, identity or inverse element, or closure operation does set A lack that makes it not a field?

It is not closed under addition.

500

Is the set of rational numbers closed under division?

(Answer cannot be stolen)

False.


You cannot divide by 0.

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