Add 2x+1 and 5x-3
7x-2
f(x)=5x+7 g(x)=6x-9 h(x)=x2+6x-7
(f-g)(x)
-x+16
f(x)=5x+7 g(x)=6x-9 h(x)=x2+6x-7
(fg)(x)
30x2-3x-63
Is this in standard form?
x3+x-67
Yes---decreasing degree of variables
What is the Partial Quotient of 6x2-3x+4 by 2x+1
3x-3
f(x)=5x+7 g(x)=6x-9 h(x)=x2+6x-7
(f+g)(x)
11x-2
f(x)=5x+7 g(x)=6x-9 h(x)=x2+6x-7
Subtract g(x) from h(x)
x2+2
f(x)=5x+7 g(x)=6x-9 h(x)=x2+6x-7
(f*g)(x)
30x-38
Can you divide using this exact polynomial with no edits?
x7+x6+x4+x3+x2+x-67
NOOOOOO
(3x3+4x2+8)/(x+2)
3x2-2x+4
f(x)=5x+7 g(x)=6x-9 h(x)=x2+6x-7
h(2)
9
What is 67x minus 6x+7
61x-7
f(x)=5x+7 g(x)=6x-9 h(x)=x2+6x-7
(fh)(1)
0
What are the coefficients in this polynomial?
x3+2x2-6x+7
1,2,-6,7
DOUBLE POINTS:
5x3-3x2-10x+24 / x+3
5x^2-18x+44+ (-108 / x+3)
f(x)=5x+7 g(x)=6x-9 h(x)=x2+6x-7
(f+h)(3)
42
f(x)=5x+7 g(x)=6x-9 h(x)=x2+6x-7
(f-g)(5)
11
f(x)=5x+7 g(x)=6x-9 h(x)=x2+6x-7
(g*h)(2)
45
T / F
x+2, c is 2F---(-2)
6x4+5x3-8x2-7x+3 / 2x2+x-1
3x2+x-3+ (-3x / 2x2+x-1)
f(x)=4x+8 h(x)=x2+6x-7
What x would make f(x) and h(x) equal
-5,3
f(x)=5x+7 g(x)=6x-9 h(x)=x2+6x+8
What x would make (f-g)(x) would equal h(x)
-8,1
f(x)=5x+7 g(x)=6x-9 h(x)=x2+6x-7
(f*g)(x) equal (h*f)(x)
No real solution
2x+5, what is c
-5/2
2x2+5x-23 / x+5
Name all parts
Divisor x+5
Dividend 2x2+5x-23
Partial 2x-5
Remainder 2
Quotient 2x-5 + (2 / x+5)