PEMDAS
( 12 - 4 ) x 3
24
( ( 3 + 2 ) x 4 ) + 5
25
Solve each side and compare using ( <, >, = )
( 12 - 4 ) x 2 _____ 12 - ( 4 x 2 )
16 > 4
( 9 ÷ 3 ) + 7
10
( 20 - ( 6 ÷ 2 ) ) + 9
26
Solve each side and compare using ( <, >, = )
( 8 - 2 ) x 3 _____ 8 - ( 2 x 3 )
18 > 2
5 x ( 9 ÷ 3 ) + ( 7 - 5 )
17
45 ÷ [ 3 x ( 2 + 1 ) ]
5
Where should the parentheses go around to make the following equation true?
8 + 2 ÷ 2 = 9
( 2 ÷ 2 )
24 ÷ ( 5 - 1 ) + ( 9 - 3 )
12
44 ÷ [ 5 + ( 2 x 3 ) ]
4
Where should the parentheses go around to make the following equation true?
6 x 3 - 4 = 14
( 6 x 3 )