Finding the Equations
Find the equation o a parabola that opens up, and has the following x intercepts
(-12,0) and (-3,0)
(x+12)(x+3)=x^2+15x+36
y=x^2+13x+40
y=(x+8)(x+5)
y=x^2-6x+13
Vertex:
y=(x-3)^2+4
Vertex:(3,4)
y=-4(x+2)^2-2
y=-4x^2-16x-18
Roots: 4 and 7
y=x^2-11x+28
Find the equation of a parabola that opens down, and has the following x intercepts
(-2,0) ad (6,0)
y=-(x+2)(x+6)
y=-x^2+8x-7
y=2x^2-50
y=2(x+5)(x-5)
y=x^2-2x-15
Vertex:
y=(x-1)^2-16
Vertex:(1,-16)
y=(x+8)^2+4
y=x^2+16x+68
Roots: -1 and 6
y=x^2-5x-6
Find the equation of a parabola that has a vertex of (-3,2) and contains the point (4,7).
y=5/49(x+3)^2+2
y=x^2-6x-27
y=(x-9)(x+3)
y=x^2+4x+29
Vertex:
y=(x+2)^2+25
Vertex:(-2,25)
y=-6(x+4)^2
y=-6x^2-48x-96
Roots: 1/2 and 5
y=2x^2-11x+5
Find the equation of a parabola that has a vertex of (0,3) and passes the x axis at (7,0)
y=-3/49(x)^2+3
y=3x^2+17x+10
y=(3x+2)(x+5)
y=3x^2+6x-13
Vertex:
y=3(x+1)^2-16
Vertex:(-1,-16)
y=-5(x-4)^2-9
y=-5x^2+40x-89
Roots: 1/4 and 3
y=4x^2-13x+3
Find the equation of a parabola that has a vertex of (5,0) and has a y intercept of (0,-12)
y=-12/25(x-5)^2
y=10x^2-19x+6
y=(2x-3)(5x-2)
y=-2x^-12x-14
Vertex:
y=-2(x+3)^2+4
Vertex:(-3,4)
y=-8(x-2)^2+8
y=-8x^2+32x-24
Roots: 5/7 and 9
y=7x^2-68x+45