Functions
Lines
Graphs
Combination of Functions
Inverse Functions
100

f(x) = 2x + 3

g(x) = 3x + 2 +x2

Find f(5) 

f(5) = 13

100

If m = 4, what is the perpendicular slope?

m = -1/4

100

Write the shift or transformation of the following equation: y = (x-2)2

Horizontal shift: 2 to the right

100

If f(x) = 2x + 3 and g(x) = 3x + 3

Find (f+g)(x)

(f+g)(x) = 5x + 6

100

If f(x) = (3,4) and (5,8) 

Find f-1(x)

f-1 = (4,3) and (8,5)

200

f(x) = 2x + 2

g(x) = x2-4x+2

Find g(4)

g(4) = 2

200

Find the slope: (2,3) (4,2)

m = -1/2

200

Write the shift or transformation of the following equation:

y = 3f(x+3)2 - 3

Horizontal shift is 3 to the left

Vertical shift is 3 down

Vertical stretch of 3

200

If f(x) = 5x + 4 and g(x) = 4x + 3

Find (f - g)(x)

(f-g)(x) = x + 1

200

Does y = x- 5 pass or fail the horizontal line test and why? 

It fails the horizontal line test because it hits graph more than once horizontally meaning that it's not an inverse function.

300

f(x) = {2x + 1,       x < 2

           3x,             2 ≤ x ≤ 4

       x2 + 2x + 3,}   x > 4

Find f(3), f(-2), f(7), and f(2)


f(3) = 9

f(-2) = -3

f(7) = 66

f(2) = 6

300

Write the point-slope form through the line (3,4) when the slope is 2

y - 4 = 2(x - 3)

300

Find the domain of the following function:

f(x) = √x-2

The domain is x ≥ 2

300

If f(x) = 2x + 2 and g(x) = 4x + 1

Find f(g(x))

f(g(x)) = 8x + 4

300

Find the inverse of the following equation:

y = 4x - 2

x/4 + 1/2 = y

400

f(x) = x3 + 5x

g(x) = x2-4x

Find f(3) and g(2)

f(3) = 42

g(2) = -4

400

Write the point-slope form through the line (2,6) and is parallel to the line 9x - 3y = 5

y - 6 = 3(x - 2)

400

The coordinates of a graph are (-5,0), (-3,1), (0, 4) and (4,2)


Find the Domain and Range of the following graph

Domain = -5 ≤ x ≤ 4


Range = 0 ≤ y ≤ 4

400

If f(x) = x2 - 2x - 63 and g(x) = 5x2 - 4x + 5

Find (g/f)(x) and the Domain

(g/f)(x) = 5x2 - 4x + 5 / 3x2 - 3

Domain of (g/f)(x): x ≠ 9 , -7

400

Find the inverse of the following equation:

y = (x-5)1/3

x+ 5 = y

500

5/x-3

Find f(4)

f(4) = 5/13

500

Write the point-slope form through the line (2,8) and is perpendicular to the line 5x + 20y = 5

y - 8 = 4(x - 2)

500

Does the graph y = -(x-3)2 have a min and a max? If it does, state the max and/or min

The graph y = -(x-3)2 has a max of (3,0)

The graph does not have a min

500

If f(x) = 3x + 4 and g(x) = 5x + 2

Find (f+g)(x+4)

(f+g)(x+4) = 8x + 38

500

Find the inverse of the following equation:

y = (5x + 6)3

x1/3/5 - 6/5 = y

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