Pipes (no end correction)
Pipes (with end correction)
Helmholtz Resonators
Intensity Level
Hearing/Voice
100

A pipe open at both ends has length 0.50 m.
Calculate the fundamental frequency.
(v=343 m/s)

λ=2L=1.00m
f=343 Hz

100

A pipe has diameter 3.0 cm.
Calculate the end correction.

e=0.3d=0.009m

100

A bottle has a cylindrical neck with diameter 2.0 cm.

Calculate the cross‑sectional area of the neck.

r=0.010m
A=πr2=3.14×10−4 m2

100

By what factor is the intensity of a 60 dB sound greater than the intensity of the quietest sound a human can hear?

10^6

100

In human voice production, what part of the system acts as the generator?

Larynx

200

A pipe open at one end and closed at the other has length 0.60 m.


Calculate the fundamental frequency.

Answer:
λ=4L=2.40 m
f=343/2.40≈143 Hz

200

A pipe open at both ends has physical length 1.20 m and diameter 4.0 cm.
Calculate the effective length.

e=0.012m
Leff=1.20+2e=1.224 m

200

A Helmholtz resonator has:

  • Neck area: 2.0×10−4 m2
  • Effective neck length: 0.020 m
  • Cavity volume: 5.0×10−4 m3

Calculate the resonance frequency.

f≈173Hz

200

By what factor is the intensity of a loud rock concert (105 dB) greater than the intensity of a quiet office (35 dB)?

10^7

200

Two people sing the same note at the same loudness, but one sounds like they are singing “ah” while the other sounds like “ee.”


What physical difference causes this?

Different vocal tract shapes, which change the formant frequencies.

300

A 0.75 m pipe is open at both ends. Calculate the third resonant frequency. 

The third resonant frequency refers to the third frequency that would be amplified if you gradually increased the driving frequency on such a tube as we did in class.

Third resonant frequency for open-open is 3rd harmonic.

λ3=2(0.75)/3=0.5 m

f3 = 343/0.5 = 686 Hz

300

A pipe open at both ends has a physical length of 1.00 m and a diameter of 5.0 cm.
What is the effective length?

e = 0.3d = 0.015 m
L_eff = L + 2e = 1.00 + 0.030 = 1.03 m

300

A bottle has:

  • Neck diameter: 2.0 cm
  • Neck length: 6.0 cm
  • Cavity radius: 5.0 cm
  • Cavity height: 12.0 cm

Assume the neck and cavity are cylindrical. Calculate the resonance frequency

A=πr^2=π(0.010)^2=3.14×10−4 m^2

V=πr^2h=π(0.050)^2(0.12)=9.42×10−4m^3

Leff=L+2e=0.060+0.012=0.072 m

f≈118Hz

300

A sound’s intensity increases by a factor of 250.
By how many decibels does the sound intensity level rise?

10log10(250)≈24 dB

300

Generally describe what a frequency spectrum of a voice looks like. How does the graph change when changing vowels but keeping the same pitch?

3 peaks where harmonics are emphasized. Same peaks are present when changing vowels, but different harmonics are emphasized due to the vocal tract resonances

400

A pipe open at one end and closed at the other has length 0.90 m. Calculate the third resonant frequency. 

The third resonant frequency refers to the third frequency that would be amplified if you gradually increased the driving frequency on such a tube as we did in class.

Third resonant frequency for open-closed is 5th harmonic.

λ=5/4L=0.72m
f=343/0.72≈476 Hz

400

A pipe is open at one end and closed at the other. Its physical length is 0.85 m and its diameter is 4.0 cm.

What is the fundamental frequency?

End correction:
e=0.3d=0.3(0.040)=0.012 m

Effective length (one open end):
Leff=L+e=0.85+0.012=0.862 m

Fundamental wavelength (open–closed):
λ=4Leff=4(0.862)=3.45 m

Frequency:
f=343/3.45≈99 Hzf 

400

A cylindrical bottle has the following dimensions:

  • Neck diameter: 2.0 cm
  • Neck length (physical): 6.0 cm
  • Cavity radius: 5.0 cm
  • Total cavity height (empty bottle): 12.0 cm

The bottle initially contains no water. How much water volume must be added to the bottle so that the Helmholtz resonance frequency becomes 150 Hz?

V≈5.8×10−4 m^3

V_initial=pi(0.050)^2(0.12)=9.42×10−4 m^3

Vwater=Vinitial−Vtarget

Vwater=3.6×10−4  m^3

400

The sound in a library has an intensity of

I_library = 2.0×10−8  W/m^2 and an intensity level of 43 dB.

Busy street traffic has an intensity of

I2 = 3.0×10−5  W/m^2

What is the intensity level (in dB) of the busy street traffic?

75 dB

400

Two sounds have the same intensity level in dB, but one is at 50 Hz and the other is at 3000 Hz.
Which will typically be perceived as louder, and why?

The 3000 Hz sound, because human hearing is most sensitive at mid‑to‑high frequencies due to our ear canal resonance.

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