PHYSICS 1 RECITATION

LESSON 1

1

IT IS A SHORTHAND METHOD FOR WRITING VERY LARGE OR SMALL NUMBER

SCIENTIFIC NOTATION

2

IT IS A COLLECTION OF QUANTITATIVE OR NUMERICAL DATA DESCRIBING A PROPERTY OF OBJECT OR EVENT

MEASUREMENT

3

HOW MANY SIG. FIGURES ARE THERE IN

14567.3?

6

4

0.35674 HAS HOW MANY SIG. FIGURES?

5

5

WHAT RULE NO. OF SIG. FIGURES TELLS THAT 

ALL ZEROS TO THE RIGHT OF THE DECIMAL POINT BUT TO THE LEFT OF A NON ZERO DIGIT ARE NOT SIGNIFICANT?

RULE #4

LESSON 2

1

has no pattern, it is inconsistent.

RANDOM ERROR

2

The closeness of the measured value to a standard or true value.

ACCURACY

3

implies the level of variation that lies in the values of several measurements of the same factor

PRECISION

4

IN ACCURACY AND PRECISION, O IS THE ________________

OBSERVED VALUE

5

are unavoidable due to several factors and it can be random OR systematic

ERROR

SOLVING1

1

1.97X10^-3 _{IS CONVERTED TO ____________________}

0.00197

2

159,000,000 IS NOTED AS

1.59X10⁸

3

32C IS EQUAL TO __________F

89.6F

4

X_{1= 55}

X_{2= 59}

_{WHAT IS THE PERCENT DIFFERENCE?}

7.02%

5

X₁=77

XT=85

WHAT IS THE PERCENT ERROR?

9.41%

SOLVING 2

1

1.768x10^-3 KM _{IS EQUALS TO ______________ IN CM}

176.8CM

2

335F IS ________C

168.33C

3

IF THERE IS 12in. in 1ft, then there is 30.48cm in them, 4ft is converted on how many in cm?

121.92cm

4

1.45x10⁵mm is _______m

145m

5

O=45.07cm, A=46cm. What is the Percent of Accuracy

97.98%

SOLVING 3

1

26KM IS _____________MM

26000000MM

2

14K IS ___________F

-434.47F

3

0.025kg IS ______mg

25000mg

4

1.779X10^-5 is equivalent to ________________

0.00001779

5

O = 45.07CM, 44.02CM, 46CM 

M= 45.03CM

FIND THE % OF PRECISION

98.5%