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John says the vertex for f(x)= x² - 6x - 13 is (-3, -13). Is he correct? If he is wrong, what is the correct vertex for this function?
No, the correct vertex is (3,-22) because vertex form of a quadratic function is f(x)= a(x-h)² + k. Since (h, k) is our vertex it would be f(x) =(x-3)² - 22. So (h, k) would be (3,-22)