Limits
Derivatives(Power Rule)
Equation of Tangent Line
Derivatives(Chain Rule)
Derivatives(Product Rule)
100

g(x)=x3 

lim g(x)=

x->-4

g(x)=(-4)3

= -64

100

y=10x3

y´=30x2

100

y=3x3-6 @ (2,18)

y-18=36(x-2)

100

f(x)=(6x2+7x)4

f´(x)=4(12x+7)(6x2+7x)3

100

f (x) = (2x^4− 3)(x^2+ 1)

f '(x) = (2x4− 3) ⋅ 2x + (x2+ 1) ⋅ 8x3

        = 12x5+ 8x3− 6x

200

Lim x4

x->-6

Lim (-6)4

=  -1296

200

y=2x12+6x7+x4

y´=24x11+42x6+4x3

200

y=x2+4x@ (7,14)

y-14=70(x-7)

200

g(t)=(4t2-3t+2)-2

g´(t)=-2(8t-3)(4t2-3t+2)-3

200

y = (−2x4− 3)(−2x2+ 1)

= (−2x4−3) ⋅ −4x + (−2x2+ 1) ⋅ −8x3

= 24x5−8x3+12x

300

f(x)= √(5 -x )

lim f(x)=

x->-3

Lim f(x)=√(5 - (-3) )

= 2.828

300

y=8x6+2x17

y´=48x5+34x16

300

y=5x2+7 @ (2,5)

y-5=20(x-2)

300

y=(x3+3)5

y´=15x2(x3+3)4

300

f (x) = (5x5+ 5)(−2x5− 3)

f '(x) = (5x5+ 5) ⋅ −10x4+ (−2x5− 3) ⋅ 25x4

= −100x9− 125x4

400

lim ( x+4 )/(x2-16)

x->-4

lim ( (-4)+4 )/((-4x)2-16)

=1/-8

400

y=1/2x-2

y´=-1/x3

400

f(x)=x2+4x3 @ x=1

y=14x-9

400

y=(-3x5+1)3

y´=-45x4(-3x5+1)2

400

f (x) = (−3 + x-3)(−4x3+ 3)

f '(x) = (−3 + x-3) ⋅ −12x2+ (−4x3+ 3) ⋅ −3x-4

= 36x2−(9/x4)

500

find: lim (x2-6x+8)/(x2-4)

x-> 2

 lim ((2)2-6(2)+8)/((2)2-4)

= - (1/2)

500

y=1/2x3/2-22/7x-5/2+x3/7

y´=3/4x1/2+55/7x-7/2+3/7x-4/7

500

f(x)=2x3+x2+5x @ x=2

y-30=33(x-2)

500

y=(-x4-3)-2

y´=8x3/(-x4-3)3

500

y = (x4+ 3)(−4x5+ 5x4+ 5)

dy/dx= (x4+ 3)(−20x4+ 20x3) + (−4x5+ 5x4+ 5) ⋅4x3

= −36x8+ 40x7− 60x4+ 80x3

M
e
n
u