x2 + 2x +1 = 3x - 10
x=½ + i√43/2
2 >= y / 5-1
y = 15
(0,2),(3,4),(-3,-2),(2,4)
Is a function?
This relation is a fuction
(3x - 2) / (x² - 9)
(-∞, -3)U(-3,3)U(3,∞)
x2 + 3x - 10
(x - 2) (x + 5)
Solve for a, 3/a + a/b= 4b
a= 2b2 + √b(4b3 - 3)
3x <= 6
x = 2
g(x) = 7x + 18 / 2
g(x) = 2x − 18/ 7
√3x+12
[-4,∞)
x2 - 9x + 18
(x - 3) (x - 6)
7y + 5 - 3y + 1= 2y+ 2
y = -2
5(x+2)-3x <= 4+2x+3(x-1)
3 <= x
g(x)= 4 - 3/2x
f(x)= 1/2x + 3/2
No, they are not inverse
√x² - 16 +5
(-∞,-4] U [4,∞)
2x2 - 5x - 12
(x - 4) (2 x + 3)
(2x-5)1/3 = 3
x = 16
x-3+2 < 10
x<11
g(x)=-2/x - 1
f(x)= -2/x+2
yes, they are inverse
√x²+9 + √x2-6x
(−∞,0] U [6,∞)
3x2 + 5x + 2
(3x+2)(x+1)
2t/k - 3 = 8/ k- 2t
t= = k +√k2 + 32 (-k + 3)/ 4
4x+4/2 > x
-2<x
f(x)= (x-2)2
√x + 2 = y
√x2−4 + 1 / x3− 27
(−∞,−2] U [2,3) U (3,∞)
8x2 - 62x + 99
(4x−9)(2x−11)