Graph the function. Find the slope,y-intercept and x-intercept, if any exist: f(x) = 3
Slope = 0; Y- Intercept = 3; X-Intercept = Does not Exist
What is the degree, leading coefficent, and constant term of the following function: f(x) = 4x3-6x7+4
Degree: 7
Leading Coefficient: -6
Constant term: 4
True or False: if x=c is not in the domain of r(x) but, when we simplify r(x), it no longer makes the denominator 0, then we have a hole at x=c.
True
Graph the function. Find the slope,y-intercept and x-intercept, if any exist: f(x) = (1-x)/2
Slope = -1/2; Y-Int = 1/2; X- Int = 1
True or False: The domain of a polynomial function is (-∞ ,∞ )
True
Find the domain: f(x) = (2x−1)/(x+1)
dom f = {x: x ≠ 0}
Graph the function. Find the slope,y-intercept and x-intercept, if any exist: f(x) = lxl - 3
Slope = -1 and 1
Y- Intercept = -3
X Intercept = +3 and -3
Determine if the following is a polynomial p(x) = (4x + x3)/x
A polynomial has all real numbers in its domain. In this function x ≠ 0. Therefore it is not a polynomial
What is the x value of the vertical asymptotes? f(x) = (2x)/(x2−3)
x= ± √3
Convert from General to Standard form. Find vertex and y intercept: f(x) =x2+x+ 1
f(x) =x2+x+ 1 =(x+12)2+3/4
y-intercept (0,1)
Domain: (−∞,∞)
Range:[3/4,∞)
Let p(x) = x3−4x2+5x−2. We know that a zero is x=1. Use long division from the root and polynomial to find the remaining zeros.
x=1; x = 2
Find the vertical asymptote and/or hole: (x2−x−6)/(x2−9)
Hole at x=3; Vertical Asymptote @ x = -3