Find absolute maximum of the function f(x) = 25 - x^2
(0, 25)
The domain of (x+1)1/2 in interval notation
[-1, inf)
The leading coefficient of f(x) = 5x3+ 3x8 - x4
3x8
The solution to 4x=7
x=log47 because log and exponential functions of same base are inverses
The conversion of 160 degrees to radians
160/x = 180/pi
x=160pi/180
=8pi/9
The equation of a line in point-slope form that passes through the points (1,2) and (-3,4)
m=2/-4 = -1/2
y-2=-1/2 (x-1)
The domain of (2x+1) / (x-5)(2x) in interval notation
x can't be zero or 5 but can be everything else
(-inf, 0) U (0,5) U (5, inf)
The end behavior of f(x)=-3x7+5x4-4x3+9
Negative LC, odd degree so end behavior is like -x3
The solution to 53x-1=5x
x=1/2
The amplitude and period of y=2sin(4x)
amplitude=2
frequency=4, so period=2pi/4 = pi/2
The composition f(g(h((x))) if f(x)=3x2-4, g(x)=2x+1, h(x)=1/x
3(2/x+1)2-4
The range of y=5x-3+1 and the equation(s) of any asymptote(s)
(1, inf) and horizontal asymptote is y=1
The result of 2x3-6x+1 divided by x-3
2x2+6x+12+ 37/(x-3)
The value of log3(815)
log3((92)5)
log3(((32)2)5)
log3(320)
=20
The value of tan-1(-1)
The range for tan-1(x) is (-pi/2, pi/2)
tan-1(-1) means we need x so that sin x / cos x = -1, which means sine and cosine must be the same value at this angle, but opposite signs (Q4)
tan-1(-1) = -pi/4
The roots of f(x)=(x^2+4x+4)/(x-1)
x=2
The domain, asymptote(s), and x-intercept of y=log5(2x+3)-1
Domain: 2x+3>0, so x>-3/2
VA: x=-3/2
x-int: (1,0) because 0=log5(2x+3)-1, so 1=log5(2x+3), so 51=2x+3, which gives x=1
The asymptote(s) of the rational function
f(x)=(x+1)(x-1) / (3x+2)(x-1)
x=1 and x=-2/3
The solution to log7(x-2)+log7(x+3)=log714
x=4
From a point on the ground 47 feet from the foot of a tree, the angle of elevation to the top of the tree is 35ยบ. Find the height of the tree to the nearest foot. (Calculator allowed)
33
The roots of the quadratic function f(x) = x^2 - 2x + 5
x=1+4i , x=1-4i
The domain and range of y=2 sin(2x-pi)-3
D: all real numbers
R: [-5,-1]
The asymptote(s) of the rational function
f(x)=(x+1)(2x-1) / (3x+2)(2x-1)(-x+3)
VA: x=-2/3, x=1/2 and x=3
The solution of log2(x-4)=3
x=4
The solution to tan(x)=1
pi/4