Equations
The slope-intercept equation that goes through (0,7) with m=-4
y=-4x+7
Use any method you know to solve
x2+2x-8=0
x= -4,2
Simplify
(3/x4)2
9/x8
Graph and draw on your board
107x+6y=439
See answer on board.
Write the point-slope equation for a line that goes through (5,7) with m=2
y-7=2(x-5)
Find the equation of the circle with center (-7,-3) and radius of 2.
(x+7)2+(y+3)2=4
Which answers are true solutions to the inequality
x=1, x=3, x=5
4<5x-1<24
Find the distance between (0,0) and (12,-9)
15
Solve graphically
x2-5x-24=0
x= 8,-3
Calculate the slope between the points (3,7) and (1,-7)
7
Write the general form equation for a line that goes through (-6,-3) and (2,5)
y-x-3=0
Solve using the quadratic equation
2x+3=x2
x= 3,-1
Factor
p2x4+fx4
x4(p2+f)
Solve
|x+10|<2
A vertical line always has this kind of slope.
Undefined
Find the parallel line to y=5x-4 which passes through (1,2)
y-5x-3
Which is a true solution to the equation?
x=2, x=8, x=15
√(289-x2) + 1 = 16
Only x=8
Find the midpoint between (0,4) and (-1,1)
(-0.5, 2.5)
Graph and write in interval notation
15≥x
See answers on board.
A horizontal line always has this kind of slope.
m=0
Find the perpendicular line to y=5x-4 which passes through (1,2)
y=-1/5x+11/5
Is it always true that |x-a|≥ 0, where a is any real number? Why or why not?
Yes! An absolute value is the distance from 0, and everything is further from 0 than 0 itself. In other words, every absolute value is positive, so it must be greater than or equal to 0.
If a quadratic equation ax2+by+c=0 has a complex solution of 5-3i, then we know 5+3i must also be a solution, because complex solutions come in these kinds of pairs.
Conjugate pairs
Write in standard notation
[-8,9)
-8≤x<9
Find the slope of the general form line
3x-4y=16
3/4