Pythagoras 1
Pythagoras 2
Trigonometry 1
Trigonometry 2
100
Was Pythagoras Greek or Roman?
Greek
100
What is the longest side of a right angled triangle? SPELL it.
hypotenuse
100
Calculate the following correct to 4 decimal places.
sin (57)
0.8387
100
When using Trigonometry, what do the letters O, A and H represent? and what is the acronym to help remember?
Opposite, Adjacent and Hypotenuse
SOH-CAH-TOA
200
When using Pythagoras Theorem, what is the formula to calculate the length of the hypotenuse?
c^2=a^2+b^2
200
When using Pythagoras Theorem, what operation is needed when finding a shorter side?
subtraction/minus
200
What is the length of BC? Round to 2dp
1.71
200
Find the size of the angle. Correct to 2 dp.
36.87
300
Calculate the length of the hypotenuse:
26
300
Calculate the length of the Hypotenuse (to 2 dp):
7.62
300
How long is side y?
8.67
300
A surfer is riding a 7m wave. the angle of depression from the surfer to the shoreline is 10 degrees. What is the distance from the surfer to the shoreline? Round to the nearest metre.
tan10=7/d
d x tan10 = 7
d = 7/ tan10
d=40m
400
Calculate x (to 2 dp):
23.24
400
Mr Goedhart rides his bicycle 21 km west and then 18 km north. How far is he from his starting point in metres?
27.66 km = 27660m
400
Mr Goedhart spots a bird sitting at the top of a 40m tall telephone pole. If the angle of elevation from the ground where he is standing to the bird is 59 degrees, how far is Mr Goedhart standing from the base of the pole?
tan59=40/d
dx tan59 = 40
d = 40/tan59
d=24m
400
You are flying a kite and have let out 80 m of string. The kite’s angle of elevation with the ground is 45°. If the string is stretched straight, how high is the kite above the ground? Correct to 2 dp
sin45= h/80
80 x sin45 = h
h=56.57m
500
A flagpole, 10m high, is supported by a wire, attached from the top of the pole to the ground. The wire is pegged into the ground 6m from the base. Determine the length of the wire. (round to 2 dp)
11.66m
500
Solve for x.
5
500
Find the length of BD. Round to the nearest whole number.
BC:
tan54 = BC/38
BC = 52.3
CD:
tan52 = CD/38
CD = 48.6
Therefore, BD = 52.3 + 48.6 = 100.9 = 101
500
What is the length of a ski run with a vertical drop of 1100m and angle of elevation of 24.4 degrees. Round to the nearest metre.
sin24.4 = 1100m/ hypotenuse
h = 1100m/sin24.4
h= 2663m