Name the x-intercepts of the function:
f(x)=(x+1)(x-7)
x-intercepts: (-1, 0) and (7, 0)
Identify the maximum value of:
f(x)=-(x+10)^2+3
The maximum value would be the y-value of the vertex (k) which is 3.
Factor
9x^2-25
(3x+5)(3x-5)
Solve:
3x^2-14=61
x=+- 5
Solve:
3x(x+4)=0
x=0 and x=-4

D.
y=-3(x-4)^2+1
Given f(x)=9x^2-8x-4 , what is the y-intercept and will the parabola open upwards or downwards?
y-intercept: (0, -4)
Opens upward because the a-value (9) is positive
Factor:
x^2+7x-44
(x+11)(x-4)
Solve:
x^2 +x=56
x=-8 and x=7
Solve the quadratic equation:
(3x-4)(x+7)=0
x=4/3 and x=-7
Determine the value of x where f(x) reaches its minimum. f(x)=(x-8)(x+15)
x=-3.5 or x=-7/2
Determine the y-intercept of:
y=-2(x+5)(x-6)
(0, 60)
Factor:
3x^2-21x
3x(x-7)
Solve:
-2(x+1)^2-5=-23
x=-4 and x=2
Solve:
2x^2+12x+4=-11
x=(-6+-sqrt6)/2
The height of a ball that is tossed in the air can be modeld by the function h(t)=-16t^2+22t+6 , where t is the time in seconds and h(t) is the height in feet. From what height was the ball launched?
6 ft.
Determine the vertex of
y=2x^2-16x+5
(4, -27)
Solve using factoring and the ZPP:
x^2-13x+40=0
x=5 and x=8
What is the sum of the solutions to the given equation?
x^2-8x-20=0
Solutions: x=-2 and x=10
Sum: 8
For which value of b will the equation have more than one real solution? 14x^2+bx+9=0 .
A. -13
B. -50
C. 1
B. -50
The height of a ball that is tossed in the air can be modeld by the function h(t)=-16t^2+22t+6 , where t is the time in seconds and h(t) is the height in feet. Determine the maximum height of the ball.
13.56 ft.
The following represent three equivalent quadratic functions. Idenify if the parabola faces upwards or downwards and then determine the y-intercept, x-intercepts and vertex.
y=-2(x+4)(x-8)
y=-2x^2+8x+64
y=-2(x-2)^2+72
y-intercept: (0, 64)
x-intercepts: (-4, 0) and (8, 0)
Vertex: (2, 72)
The expression (2x-11)(4x+7) is equivalent to the expression ax^2+bx+c . What is the value of b?
b=-30
The height of a ball that is tossed in the air can be modeld by the function h(t)=-16t^2+22t+6 , where t is the time in seconds and h(t) is the height in feet. When will the ball land on the ground?
1.6 seconds
What is the positive solution to the given equation?
4x^2-3x-27=0
x=3