Determine the vertex form for the following from the given function.
y=x^2+12x+32
y=(x+6)^2-4
400
Parent function: y=x^2
How does this function affect the graph and sketch it roughly: y=x^2+2
How does this function affect the graph and sketch it roughly: y=(x-3)^2
y=x^2+2 up two units
y=(x-3)^2 two units left
400
Solve by factoring: 2x^2-3x+9
(2x-3)(x+3)
400
Complete the square and solve:
x^2-18x=-72
x=9±3
x=12, x=6
400
Solve the quadratic function using the quadratic formula:
3x^2-4x-1=0
4±2√7
_____
6
400
Write in vertex form and state the vertex
y=x^2+10x+27
y=(x+5)^2+2
500
What are the solutions of this function?
Is this graph a min or a max?
What is the domain and range?
x=1, x=3
Minimum
Domain = all real numbers
Range = y≥-1
500
Factor: 3pz+5z-9p-15
(z-3)(3p+5)
500
Complete the square and solve:
3x^2-12x+6=0
x=2±√2
500
Solve the quadratic function using the quadratic formula:
4t^2-16t+4=0
2±√3
500
From the given function, determine the axis of symmetry, vertex, and y intercept.
y=(x+5)^2+2
Axis of symmetry: x=-5
Vertex: (-5,2)
Y-int: (0,27)