A
B
C
D
E
100

what is the name of this symbol?

 ≥ 

greater than or equal to

100

what is the standard form of the quadratic equation

ax2+bx+c=0

100

in 6x2-17x+12=0, what is the leading coefficient?

6

100

what are the symbols for quadratic inequalities?

>,≤ ,<,≥ 

100

which of the following is rational number?

a.    √12                    c.1.23452156

b.    √15                   d.-249

d. -249

200

in 6x2-17x+12=0, which is the quadratic term?

6x2

200

which is the irrational number?

a. √ 49                      b. 9.454545

c. 7/8                        d.√2312

 d.√2312

200

what is the formula for sum and product of the quadratic equation

sum: -b/a

product: c/a

200

write the fomula for Discriminant

b-4ac

200

 if a=1 b=-8 c=16, write  in the standard form

x2-8x+16=0

300

give the discriminant value of x2-4x+5=0

D=-4

300

what is the nature of value of the discriminant;

D= -14

not real/ imaginary

300

find the sum and the product of the roots of the quadratic equation 6x2+12x-18=0

sum:2

product:-3

300

find the sum and the product of the roots of the quadratic equation 2x2+8x-10=0

sum: -4

product: -5

300

what do yu call in the method of solving the quadratic equation x2=k?

extracting square roots 

400

what is the nature of roots of x2-6x+7=0

Since D=8 and it is not a perfect square then it is real, irrational and unequal

400

give the quadratic formula

x = (-b ± √(b² - 4ac)) / (2a).

400

find the roots of x2 +3x - 10<0

x= -5

x=2

400

give the discriminant value of 2x² + 4x + 2 = 0

D=0

400

what is the nature of value of the discriminant is positive but not a perfect square

real, irrational, and unequal

500

find the roots of the quadratic equation 2x2+8x-10=0

x=1

x=-5

500

find the  roots of the quadratic equation 6x2+12x-18=0

x= -1

x= 3

500

what are the roots of x2-2x-8≥ 0

x=4 

x=-2

500

Write the equation in the form of ax2+bx+c=0 which the given numbers are solution.

x=8

x=10

(x-8)(x-10)=0

x2-10x-8x+80=0

x2-18x+80=0

500

Write the equation in the form of ax2+bx+c=0 which the given numbers are solution.

x=-5

x=1

(x+5)(x-1)=0

x2-1x+5x-5=0

x2+4x-5=0

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