(Photo)Graph
What is/are the solutions to this quadratic?
x=-1,3
I am the math symbol created by using a square root
What is
pm
Factor:
x^2+4x+3
(x+1)(x+3)
What number would complete this square?
x^2+10x
25
I am the quadratic formula
x={-bpmsqrt{b^2-4ac}}/{2a}
Which direction does this parabola open?
y=8x^2
Up
Solve:
x^2-4=0
x=pm2
Solve:
x^2=9
x=pm3
Solve by factoring:
x^2-5x+6=0
x=2,3
Solve:
x^2+4x+1=0
x=-2pmsqrt3
Solve:
3x^2+2x+1=0
x=-{1pmsqrt2i}/3
Find the vertex:
y=(x-5)^2+11
(5,11)
Solve:
x^2-4x-5=0
x=-1,5
Solve:
5x^2-80=0
x=pm4
Solve:
x^2+3x-40=0
x=-8,5
Solve:
x^2+6x+3=0
x=-3pmsqrt6
Solve:
5x^2+8x+3=0
x=-3/5,-1
Find P
x=1/12(y+3)^2-5
p=3
Solve:
2x^2+7x+3=0
x=-3,-1/2
Solve:
3x^2-81=0
x=pm3sqrt3
Solve:
x^2-6x-91=0
x=-7,13
Solve:
2x^2-8x+10=0
x=2pmi
Solve:
4x^2+2x-7=0
x=-{1pmsqrt{29}}/4
Find the focus:
y=2(x-1)^2+7
(1,57/8)
Solve:
x^2-2x-3.84=0
x=-1.2,3.2
Solve
7x^2+2401=0
x=pm7sqrt7i
Solve:
x^2-5x-300=0
x=-15,20
Solve:
x^2+x+1=0
x=-{1pmsqrt3i}/2
Solve:
x^2-8x+27=0
x=4pmsqrt{11}i
Find all parts of:
x=1/8(y+8)^2-6
Vertex: (-6,-8)
Focus: (-4,-8)
Directrix: x=-8
Axis of Symmetry: y=-8