Solving by Factoring
Factor the equation:
x^2-2x-3=0
x = -3, 1
When you take the square root in the context of a quadratic equation, what must you ALWAYS get on the other side of the equation?
Plus OR minus. You need both!
What's the quadratic formula?
x=(-b+-sqrt(b^2-4ac))/(2a)
What are two other names for 'vertex'?
Minimum or maximum
Solve for x:
4x-6=30
x = 9
Factor the equation:
x^2+7x+10=0
x=-5,-2
Solve for x using square roots:
2x^2=18
x=3,-3
Use the quadratic formula to solve:
x^2-5x-14=0
x = 7, -2
Find the vertex of the parabola given by:
y=x^2-1
(0, -1)
Simplify:
9-2x<5
x >2
Factor the equation:
x^2-10x+22=-2
x = 6, 4
Solve for x using square roots:
5x^2=80
x=4, -4
Use the quadratic formula to solve:
y=2x^2+3x-20=0
x=-4, 5/2
Find the vertex of the parabola given by:
y=(x-2)^2+8
(2, 8)
In the equation y=mx+b, what does b represent, and where would you find it if you graphed it?
Factor the equation:
7x^2-14x=-7
x = 1
Solve for x using square roots:
x^2+8 =80
x=+-sqrt72
Use the quadratic formula to solve:
y=x^2+4x+7
No can do! x is not real!
Find the vertex of the parabola given by:
y=(x-9)^2+6
(9, 6)
Find the sum:
(3y^2+y^3-5)+(4y^2-4y+2y^3+8)
3y^3+7y^2-4y+3
Factor the equation:
6x^2-18x-18=6
x = 4, -1
Solve for x using square roots:
9x^2+10=91
x=3, -3
Use the quadratic formula to solve:
5x^+9x=-4
x = -4/5, -1
Find the vertex of the parabola given by:
y=x^2+6x-3
(-3, -12)
Find the product:
(y - 3)(y+7)
y^2+4y-21