What's my factors?
Factor 25x2 - 30x + 9
(5x - 3)(5x + 3)
Find the vertex:
f(x) = 2x2 - 12x + 7
(3, -11)
Find the zeros:
f(x) = -3x2 + 5x
x = 0 or x = 5/3
What would be the quadratic equation when the zeros are (-5, 0) and (-6, 0) with a y-intercept of 30?
y = (x + 5)(x + 6)
What equation has x-intercepts of (2, 0) and (6, 0) with a maximum at (4, 2)?
y = -1/2(x - 2) (x - 6)
Factor (10x2 - 15x - 100)
5(2x + 5)(x - 4)
Find the vertex:
y = 4(x - 6)2 - 7
(6, - 7)
Solve -3 = -2x2 + 5x
x = -1/2 or x = 3
What would be the quadratic equation if the x-intercepts are -8 and 7 and is concave down?
f(x) = a(x + 8)(x -7) when a-value is negative
Solve 49x2 - 70x = -25
x = 5/7
Find the vertex:
f(x) = -x2 - 8x + 5
(-4, 21)
Solve: 6x2 - 2x = -1
No real solution OR x = (4 +- isqrt (20))/12
OR x = (4 +- 2i sqrt(5))/12
OR x = 1/3 +-( i sqrt(5))/6
Write the quadratic function with x-intercepts of -2 and 4 with a vertex of (1, 5).
y = -5/9 (x + 2)(x - 4)
Factor
6x^3 + 3x^2 - 3x
3x(2x - 1)(x + 1)
Factor 8x2 + 4x - 60
4(x+3)(2x-5)
Find the vertex:
y = 2x2 + 4x
(-1, -2)
Solve 2x2 - 2x = x + 1
x = (3 +- sqrt (17))/4
What would be the equation of a quadratic with zeros of 1 and -1/2 and is concave up?
**Factored form should NOT have factions in it!
y = a(2x - 1)(x - 1) when a-value is positive.
What would the y-value be so the equation would have only ONE solution?
y = 2x2 - 12x + 7
-11 = 2x2 - 12x + 7
so y = -11
Factor 63x2 - 210x + 175
7(3x-5)2 or 7(3x-5)(3x-5)
Find the vertex: f(x) = 3x2 + 5x + 4
(-5/6, 23/12)
Solve: 49x2 - 25 = 24x
x = 1 or x = -25/49
Write an equation with x-intercepts of (-3, 0) and (-12, 0) and passes through the point of (2, 10).
y = 1/7(x+3)(x+12)
What would the y-value be so the equation would have NO real solution?
y = 2x2 - 12x + 7
Any y-value where y < -11