y=____when we want to find the x-intercepts.
0
x=____ when we want to find the y-intercept.
x=0
For x2+2x=y, will the parabola be open upwards or downwards?
Upwards
When finding the LOS, we solve for x=______
a number.
point: (x,y)
The x-intercepts of (x-1)(x-2)=y are ______.
(1,0) and (2,0)
For y=-x2+2x: a=____, b=_____, c=_____
-1; 4; 0
x=-2
The vertex for x2-4x+4 is _______.
(2,0)
Our x-intercepts should be _____.
coordinates; points; (a number, 0)
The y-intercept for x2=y is ______.
(0,0)
y=a(x-h)2+k is the ____ form of a quadractic.
vertex
x=2
The vertex of y=8(x+6)2-4 is _____.
(-6,-4)
The x-intercepts for (2x+8)(-3x+12)=y are_____.
(-4,0) and (4,0)
The y-intercept for x2+2x-24=y is _______.
(0,-24)
y=ax2+bx+c is the _____ form of a quadratic.
standard
The two ways to find LOS are LOS = ______ or
LOS = ______.
-(b)/2a; (x1+x2)/2
The vertex for -x2+3x+2 is _______.
(1.5,4.25)
The x-intercepts for x2+2x-24 are ______.
(4,0) and (-6,0).
The y-intercept for 8(x+1)2+2=y is ______.
(0,10)
The name of the graph of a quadratic equation is a _____.
parabola
x=-12
We use ______ value from the _____ and plug it into our _______ to find the _____ value of the vertex.
x; LOS; original (and/or factored) equation