What is the vertex of the of the following quadratic equation: f(x) = 2(x-5)2+3
V = (5, 3)
What are the zeros of this polynomial? (approximate)
x = -2.5, 1 and 7
Simplify the following
3sqrt(50) - 2sqrt(18) + 7sqrt(2) - sqrt(32)
12sqrt(2)
Use synthetic division and determine is (x+2) a factor of 2x3+2x2−x+6?
Yes it is, remainder = 0
Solve for x: (3x+10)1/2 - 5 = 2
What is 13
Solve: 2x2+3x-20 = 0
(hint: quadratic formula)
x = 5/2 and -4
Find the zeros of the following by factoring:
f(x) = 3x3-12x2+9x
(hint: factor out a GCF first)
x = 0, 1 and 3
Simplify the following two expressions
x3y2z 7throot(x2z)
xy5z4 4throot(x2y3)
Factor and find the zeros
3x2+10x-8
(3x-2)(x+4)
x = 2/3 and -4
Divide 4x4-6x3+2x2-5x+7 by 2x2+1
2x2-3x + (-2x+7)/(2x2+1)
Final Jeopardy:
Find the zeros and graph the following: x2-8x+15
zeros x = 3 and 5
graphs: check desmos