Find the Asymptote
y=2/(x-3) +4
3/2+1/x=2
y=8/(x+3) - 3
3/(4x) = 5/(x+2)
What is/are the vertical asymptote/totes of the following rational function?
y=(x+5)/(x^2 -25)
8/(x+2)+8/2=5
y=(x^3 -1)/(x+4)
(-3)/(x+1)=4/(x-1)
y=(6x^4 + 3x^2 -6)/(12x^4 -3x+2)
(x-3)/(x-4)+4=(3x)/x