Inverse Variation/The Reciprocal Functions
What is the horizontal asymptote of the following:
f(x)=1/(x+4)+6
y=6
Find the vertical asymptote(s)
f(x)=(x-5)/(x-7)
x=7
Identify the horizontal asymptote:
f(x)=(6x^3)/(3x^3)
y = 2
Find the x-intercept(s):
f(x)=(x-3)/(x-4)
Identify the horizontal and vertical asymptotes based on the function below:
f(x)=1/(x-4)+9
vertical asymptote: x=4
horizontal asymptote: y=9
What is the vertical asymptote of the equation below:
f(x)=1/(x+3)-2
x=-3
Find the vertical asymptote(s)
f(x)=(x^2+10x+16)/(3x+12)
x=-4
Identify the horizontal asymptote:
f(x)=(x^2+6x+8)/(x^3-8)
y=0
Find the y-intercept(s):
f(x)=(x+10)/(x+5)
(0,2)
Identify the vertical asymptote(s):
f(x)=(x^2-16)/(5x-15)
x=3
If x and y vary inversely and x = 10 and y = 4, what is the constant of variation?
40
Find the vertical asymptote(s):
f(x)=(3x^3)/(2x^2
x = 0
Identify the horizontal asymptote:
f(x)=(x^2+x^4)/(x^3)
y = 0
Find the y-intercept(s):
f(x)=(x^2-8x+12)/(x-4)
(0,-3)
Identify the y-intercept:
f(x)=(x^2+9x+18)/(x^2-6)
(0,-3)
If x and y vary inversely and x = -2 and y = 6, find y when x = 4
y = - 3
Find the vertical asymptote(s):
f(x)=(x^3)/(x^2-49)
x = 7, x = -7
Identify the horizontal asymptote:
f(x)=(x+4)/(x-9)
y = 1
Find the x-intercept(s):
f(x)=(x^2-8x+12)/(x-4)
Identify the horizontal asymptote
f(x)=(6x^3)/(x^2-x^3)
y=-6
If x and y vary inversely and x = 2, when y = 1/2, find x when y = 5
x = 1/5
Find the vertical asymptote(s):
f(x)=(-3x)/(x^2+9x+18)
x = -3, x= -6
Identify the horizontal asymptote:
f(x)=(3x^2+12x^4)/(2x^2+6x^4)
y = 2
Find the x and y intercept(s):
f(x)=(x^2)/x
y-intercept: undefined
x-intercept: (0,0)
Identify the y-intercept:
f(x)=(x^3)/(x-9)
(0,0)