Red Oxen
Which species could be reduced to form NO2?
a) N2O
b) NO3–
c) HNO2
d) NO
b) NO3–
Which changes could take place at the positive electrode (cathode) in a voltaic cell?
I. Zn2+(aq) to Zn(s)
II. Cl2(g) to Cl–(aq)
III. Mg(s) to Mg2+(aq)
I and II only
Consider the following reactions of three unknown metals X, Y and Z.
2XNO3(aq) + Y(s) → 2X(s) + Y(NO3)2(aq)
Y(NO3)2(aq) + Z(s) → No reaction
2XNO3(aq) + Z(s) → 2X(s) + Z(NO3)2(aq)
What is the order of increasing reactivity of the metals (least reactive first)?
X < Z < Y
What happens to the manganese in the following reaction?
2MnO4–(aq) + 5H2O2(aq) + 6H+(aq) → 2Mn2+(aq) + 8H2O(l) + 5O2(g)
It is reduced and its oxidation number decreases.
What are the features of a standard hydrogen electrode?
I.A temperature of 298 K
II.A carbon electrode
III.Hydrogen gas at 1.01 × 105 Pa (1 atm) pressure
I and III only
The standard electrode potentials for two metals are given below.
Al3+(aq) + 3e– Al(s) EO = –1.66 V
Ni2+(aq) + 2e– Ni(s)EO = –0.23 V
What is the equation and cell potential for the spontaneous reaction that occurs?
2Al(s) + 3Ni2+(aq) → 2Al3+(aq) + 3Ni(s) EO = 1.43 V
State which of the species is the strongest oxidizing agent
Fe2+(aq) + 2e– Fe(s) –0.45 V
H+(aq) + e– H2(g) 0.00 V
Br2(l) + e– Br–(aq) +1.07 V
Bromine/Br2
Which is the strongest reducing agent according to the spontaneous reactions below?
2Cr(s) + 3Fe2+(aq) -> 2Cr3+(aq) + 3Fe(s)
Fe(s) + Pb2+(aq) -> Fe2+(aq) + Pb(s)
Cr(s)
Deduce the order of reactivity of the four metals, cadmium, nickel, silver and zinc in the below equations and list in order of decreasing reactivity
Cd(s) + Ni2+(aq) → Cd2+(aq) + Ni(s)
Ni(s) + 2Ag+(aq) → Ni2+(aq) + 2Ag(s)
Zn(s) + Cd2+(aq) → Zn2+(aq) + Cd(s)
Zn > Cd > Ni > Ag
Nitrogen monoxide may be removed from industrial emissions via a reaction with ammonia as shown by the equation below.
4NH3(g) + 6NO(g) → 5N2(g) + 6H2O(l)
Deduce the oxidation and reduction half-equations and identify the oxidizing agent for the reaction.
Oxidation: 2NH3 → N2 + 6H+ + 6e–
Reduction: 2NO + 4H+ + 4e– → N2 + 2H2O oxidizing agent: NO
Deduce the equations for the formation of the major product at the positive electrode (anode) when the following aqueous solutions are electrolysed. •dilute sodium chloride •concentrated sodium chloride
Dilute sodium chloride: 2H2O → O2 + 4H+ + 4e– / 4OH– → O2 + 2H2O + 4e– Concentrated sodium chloride: 2Cl– → Cl2 + 2e–
Draw a labelled diagram of a voltaic cell made from an Fe(s) / Fe2+(aq) half-cell connected to a Cu(s) / Cu2+(aq) half-cell. In your diagram identify the positive electrode (cathode), the negative electrode (anode) and the direction of electron flow in the external circuit. And deduce the half-equations for the reactions taking place at the positive electrode (cathode) and negative electrode (anode) of this voltaic cell.
diagram has salt bridge, voltmeter electrodes; positive electrode (Cu):cathode and negative electrode (Fe):anode flow of electrons: from Fe to Cu positive electrode: Cu2+ + 2e– → Cu; negative electrode: Fe → Fe2+ + 2e–;
The amount of ethanol, C2H5OH(aq), in a person’s breath can be measured in an electrochemical cell. The relevant half-reaction equations are given below. Which reaction occurs at the cathode?
I CH3COOH(aq) + 4 H+(aq) + 4 e– → C2H5OH(aq) + H2O(l) E° = +0.58 V
II O2(g) + 4 H+(aq) + 4 e– → 2 H2O(l) E° = +1.23 V
O2(g) + 4 H+(aq) + 4 e– → 2 H2O(l)
The following equations indicate reactions that occur spontaneously.
Fe(s) + NiCl2(aq) → FeCl2(aq) + Ni(s)
Zn(s) + FeCl2(aq) → ZnCl2(aq) + Fe(s)
Ni(s) + PbCl2(aq) → NiCl2(aq) + Pb(s)
Which is the increasing order of the reactivity of the metals?
Pb < Ni < Fe < Zn
Which of the following metals will act spontaneously as reducing agents with silver iodide but not with silver sulfide?
A. Hg(l) and Cu(s)
B. Cr(s) and Al(s)
C. Ni(s) and Co(s)
D. Au(s) and Mg(s)
C. Ni(s) and Co(s)
Draw an electrolytic cell illustrating the electrolysis of molten nickel(II) bromide, NiBr2. Include in the diagram the direction of the electron flow, the polarity of electrodes and state the half-equations for the product formed at each electrode.
- Cathode/negative electrode equation: Ni2+ + 2e– → Ni - Anode/positive electrode equation: 2Br– → Br2 + 2e– - power source present, electron flow from anode to cathode - molten electrolyte/Ni2+(l) and Br–(l)/NiBr2(l)

Complete the sentence:
A zinc–carbon cell is an example of i cell. The moist paste of ammonium chloride allows for the flow of ii .
a voltaic and ions
If the reference half-cell were changed from the standard hydrogen half-cell to the standard cadmium half-cell, then the reduction potential for the following equation would become
CH3COOH(aq) + 4 H+(aq) + 4 e– → C2H5OH(aq) + H2O(l) E° = +0.58 V
+0.98 V
A 150 mL sample of H2SO3(aq) required 31.5 mL of 0.0100 mol/L acidified KMnO4(aq) to completely react. The concentration of H2SO3(aq) in the sample was
5.25 mmol/L