A number plus itself, plus twice itself, plus 4 times itself, is equal to −104. What is the number?
-13
\text{Solve for } A \text{: } P = \frac{A}{B+C}
A= P(B+C) \text{ or } A = PB+PC
4x^5\cdot 3x^7
12x^12
\sqrt{256}
16
(x+3)(x-2)
x^2+x-6
3x^2-12x
3x(x-4)
x^2-49=0
x = \pm 7
What is Mr. Heri's favorite subject?
English Composition!
7x−2(x+4)=27
7
\text{Solve for } T_1 \text{: } \frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}
T_1 = \frac{P_1 V_1 T_2}{P_2 V_2}
(t^2)^3(t^3)^4(t^0)^100
t^18
\sqrt{63y^4}
3y^2\sqrt{7}
(2x-5)(2x+5)
4x^2-25
y^2-11y+24
(y-3)(y-8)
x^2-14x+49=0
x=7
\text{State } \pi \text{ to more than 3 digits}.
3.14159265358979323846...
Jay’s father is twice as old as Jay. In 20 years, Jay will be two-thirds as old as his father. How old is each now?
Jay: 20, His dad: 40
\text{Solve for } r \text{: } A =(1 + \frac{rt}{n})
r = \frac{n(A-P)}{Pt} \text{ or } r = \frac{n}{t}(\frac{A}{P}-1)
[(2p)^{2/9}]^3\cdot (2p)^{1/3}
2p
7\sqrt{198}
21\sqrt{22}
(3x-4)^2
9x^2-24x+16
4q^2-36
4(q-3)(q+3)
x^2+6 = 7x
x=1,6
What grade is Mr. Heri in, what is he studying, and where is he studying it?
Graduate student in Pure/Theoretical Math at Sac State :)
(2x−9)/5+ (3x+1)/10 = (x+7)/4
23/3
\text{Solve for } \pi \text{: } A = 2\pi r^2 + 2\pi r h
\pi = \frac{A}{2r^2 + 2rh} \text{ or } \pi = \frac{A}{2r(r+h)}
(\frac{-7a^2b^3c^0}{3a^3b^4c^3})^-4
\frac{81a^4b^4c^12}{2401}
\sqrt{150k^15l^25p^35}
5k^7l^{12}p^{17}\sqrt{6klp}
(x^2+3y)(2x^2-5y)
2x^4+x^2y-15y^2
2k^2+7k-4
(2k-1)(k+4)
4x^2-16x=0
x=0,4
Sing the Quadratic Formula song
🎼🎵🎶
The sum of three consecutive odd integers is 255. What are the integers?
83, 85, 87
\text{Solve for } r \text{: } A = \frac{P(1+r)^t}{k}
r = \root{t}{\frac{Ak}{P}}-1
\text{Express the following in the form } x^k \text{: } \root(3){h\cdot\sqrt{h\cdot \root(4){h}}}
h^{13/24}
\root(5){32(x-3)^{15}(x^2+4)^5}
2(x-3)^3(x^2+4)
(2x-4)(x^2+4x-5)
2x^3+4x^2-26x+20
30x^2+15x-225
15(2x-5)(x+3)
x^2 +15x -10 = 15x-5
x= \pm\sqrt{5}
What is the most important theorem in algebra? State what it says/means.
Fundamental Theorem of Algebra (FTA)
3x+6=7-3x-2x^2
x= \frac{-3 \pm \sqrt{11}}{2}