Review - Advanced Mechanics and Electromagnetism

Random 1

100

A projectile is launched on Earth with an initial speed of 25 m/s at an angle of 40 degrees to the horizontal.

Give the final y velocity at the peak height.

0

200

A projectile is launched on Earth with an initial speed of 25 m/s at an angle of 40 degrees to the horizontal.

Find the intial y velocity.

= 25 Sin 40

uy= 16 m/s

300

A projectile is launched on Earth with an initial speed of 25 m/s at an angle of 40 degrees to the horizontal. The initial y velocity is 16.06 m/s.

Indicate the type of formula/equation we would use. 

v² = u² + 2as  

400

A projectile is launched on Earth with an initial speed of 25 m/s at an angle of 40 degrees to the horizontal.

a) Find the maximum height reached by the projectile given the initial y velocity is 16.06 m/s.

vy = 0   uy = 16.06 m/s

v2 = u2 + 2as  

02 = 16.62 + 2(9.8)s

0 = 275.56 + 19.6s

-275.56 = 19.6s

s = 13.159 m

500

Describe the HORIZONTAL and VERTICAL components of projectile motion.

Vertical Component:

• The vertical component of projectile motion is influenced by gravity. When an object is launched into the air, it follows a curved path due to the gravitational force acting on it.
• The vertical velocity of the object changes as it moves upward against gravity and then downward with gravity.
• At the peak of its trajectory, the vertical velocity is momentarily zero before the object begins to descend.

Horizontal Component:

• The horizontal component of projectile motion refers to the motion of the object parallel to the ground. In the absence of air resistance, the horizontal velocity of the object remains constant throughout its flight.
• The horizontal distance traveled by the object is determined by its initial horizontal velocity and the time of flight.

Random 2

100

The turning effect that is produced by a force.

T_________

Torque

200

Calculate the torque given the lever arm is 56 cm. The angle between the applied force is 50 degrees. The applied force is 30 N.

What is one FACTOR that needs to be converted to an SI unit?

56 cm to 0.56 m

300

Calculate the torque given the lever arm is 56 cm. The angle between the applied force is 50 degrees. The applied force is 30 N.

Torque = rf Sin (pheta)

Torque = 0.56 x 30 Sin 50

Torque = 12.87 N m

400

Give the WORK DONE formula.

Work = force x distance

Work = Change in energy

Work = KE = 1/2 mv²

500

Calculate the work done on a LEO satellite that has a mass of 1500 kg and is 2000 km above Earth's surface. Given g is 6 m/s/s.

W = F x d

W = mg x d

W = 1500(6) x 2000

W = 18 000 000 000 J

Random 3

100

What letter represents each of the following;

F = 

I1 = 

I2 =

r = 

L = 

F = force between two current carrying conductors

I1 = Current in first conductor

I2 = Current in second conductor

r = distance between the two conductors

L = length of the conductor

200

Centripetal force proportionally related to the VELOCITY. Therefore, an increase in the velocity results in an

A rise in the CENTRIPETAL FORCE.

300

Centripetal force is inversely proportional to the RADIUS.

A decrease in the RADIUS results in a ______ in the CENTRIPETAL FORCE. 

Centripetal force is inversely proportional to the RADIUS.

A decrease in the RADIUS results in a increase in the CENTRIPETAL FORCE. 

400

Calculate the gravitational force on a 1000kg satellite that is positioned 8km above the Earth's surface given an acceleration due to gravity of 9 m/s/s.

F = m*g

where:
m is the mass of the object,
g is the acceleration due to gravity.

Given that the mass (m) of the satellite is 1000 kg and the acceleration due to gravity (g) is 9 m/s², you can substitute these values into the formula:

F = 1000 kg * 9 m/s² = 9000 N

So, the gravitational force on a 1000 kg satellite positioned 8 km above the Earth's surface, with an acceleration due to gravity of 9 m/s², is 9000 Newtons.

500

Calculate the force between two current carrying wires which experience 4A of current moving in the same direction.

The length of each wire is 0.3m and the distance between each wire is 0.2m with

he force between two parallel current-carrying wires can be calculated using Ampere's law. The formula is:

F = (μ0 * I1 * I2 * L) / (2π * r)

F = (4π * 10^-7 T*m/A * 4A * 4A * 0.3m) / (2π * 0.2m)

Upon simplifying, we find:

F = 0.00000024 N

Random 4

100

r = m v / q B

What does v represent?

velocity

200

r = m v / q B

What does q and B represent?

charge on particle within a magnetic field

300

Give the charge and mass of an electron.

mass = 9.109 x 10^-31

charge = 1.602 x 10^-19

400

An electron moves at a velocity of 3m/s in a field that has a magnetic field strength of 2T. Calculate the radius of the electron.

r = (9.109 x 10^-31)(3) / (1.602 x 10^-19)(2)

r = 2.73 x 10^-30 / 3.204 x 10^-19

r = 8.51 x 10^-12 m

500

An electron at rest is accelerated to 2.3 × 10^4 m/s by two parallel electric plates. Calculate the work done on the electron.

K = ½  (9.11 x 10^-31 kg)(2.3 x 10^4 m/s)^2

= 2.42 x 10^-21 J

Random 5

100

K = ½  mv²

^{What does m represent?}

Mass

200

K = ½  mv²

^{What does K and V represent?}

K = Kinetic energy

v = velocity

300

W = q V

What does W,  q and V represent?

W = Work done

q = charge

V = voltage or potential difference

400

If the work done on the electron is approximately 2.42 x 10^-21 joules then calculate the potential difference (voltage).

V = W / q

where:
W = work done (2.42 x 10^-21 J)
q = elementary charge (charge of the electron, approximately 1.6 x 10^-19 C)

Substituting these values, the potential difference is:

V = 2.42 x 10^-21 J / 1.6 x 10^-19 C = 15.125 V

500

Most transformers are NOT 100% effici__________ as energy is lost due to Eddy c_________

efficient

Eddy currents