What is the derivative of f(x) = (3x+1)2?
2(3x+1)(3)
-x/y
3cos(3t)
y = cot(3t), what's y'??
-csc2(3t)(3)
Find dy/dx if 1/y + 1/x2 = 1
-2y2/x3
Find y' for x3+y3 = 4.
- x2/y2
f(x) = (6x2+7x)4 , f'(x) =
4(6x2+7x)(12x + 7)
y = sin(3x + 4y). Find y'
[ 3cos(3x + 4y) ] / [ 1 - 4cos(3x+4y)]
Find y' for y = (4x+x-5)1/3
(1/3)(4x+x-5)-2/3(4-5x-6)
What's the derivative of sin(3t) / (1+t2)
[3cos(3t)(1+t2) - (2t)sin(3t) ] / (1+t2)2
Find y' for x3y5 + 3x = 8y3+1.
(3x2y5+3) / (24y2-5x3y4)
Find the slope of the curve x2y + y4 = 4 + 2x at the point (-1, 1).
4/5
-3sin(3w)sec(1-w) - cos(3w)sec(1-w)tan(1-w)
If y = sin(3x + 4y), y'=
[ 3cos(3x+4y) ] / [ 1 - 4cos(3x+4y) ]
h(z) = tan4(z2+1), h'(z) =
Tip: How many functions can you see that composed gets you h(z)?
4tan3(z2+1)sec2(z2+1)(2z)