Factoring trinomials when a=1
Factor into two binomials: x2+10x+25
(x+5)(x+5)
Factor 2x2-7x+6
(2x-3)(x-2)
Solve the following equation:
x2 + 5x + 6 =0
x = -2, x = -3
Factor: x2 + 6x + 9
(x+3)(x+3)
Factor: x2-16
(x+4)(x-4)
Factor into two binomials: x2-12x+27
(x-9)(x-3)
Factor 9x2+6x+1
(3x+1)(3x+1)
Solve the following equation:
x2 + x - 12 =0
x = -4, x = 3
Factor completely: x2 +18x - 40
(x+20)(x-2)
Factor: 9-x2
(3+x)(3-x)
Factor into two binomials: x2+2x-24
(x+6)(x-4)
Factor 2x2-x-6
(x-2)(2x+3)
Solve the following equation using factoring:
x2 + 12x + 32 =0
x = -8, x = -4
Solve using factoring: x2 - x - 72 = 0
x = 9 and x = -8
25y2-4k2
(5y+2k)(5y-2k)
Factor into two binomials: x2-5x-84
(x-12)(x+7)
Factor 4y2+12y+9
(2y+3)(2y+3)
Solve the following equation using factoring:
x2 + 17x -200 =0
x = -25, x =8
Factor completely: 4x2+ 14x + 10
(2x + 5) (2x+ 2)
16x2 - 49
(4x-7)(4x+7)
Factor into two binomials: y^4-7y^2-18
(y^2-9)(y^2-2)
Factor: 5x2+23x-10
(5x-2)(x+5)
Solve the following equation using factoring:
3x2 + 11x + 6 =0
x = -2/3 and x = -3
Solve using factoring: 3x2 - 5x - 2
(3x +1)(x-2) so x = -1/3 and 2
x2-225
(x-15)(x+15)