Evaluate
5x+4 when x=7
39
5a-a
4a
6x=48
x=8
Write the equation of a line in slope-Intercept form that has a slope of 4 and a y-intercept of (0, 8)
y=4x+8
What are the three ways to solve a system, of equations?
graphing, substitution, and elimination
17 - x when x=-3
20
-5a-4a+b
-9a+b
-x/3 = 27
x=-9
Find the slope between the points (3, 7) and (8, 27)
m=4
Is the point (4, 5) a solution to the system?
2x+3y=23
-x+10y=46
yes
3(x-4)+5x when x=10
68
6r+3s+2s+4r
10r+5s
6(n-4)=3n
n=8
In point-slope form (y-y1=m(x-x1)), if you're given a point on the graph, where do you plug in the values of the coordinate?
x1 and y1
Add the equations
4x+8y=-20
-3x+2y=30
x+10y=10
4a+7b+3a-2b+2a when a=-5 and b=3
-30
7b-(3a-8b)
15b-3a
7w+2=3w+94
w=23
Find the x and y intercepts of the equation
3x+8y=48
(16, 0) and (0, 6)
Solve with substitution
y=x-2
3x-y=16
(7, 5)
4(2m-n)-3(2m-n) when m=-15 and n=-18
-12
4(3x+8y)-2(5x-3y)
2x+38y
Solve A=1/2 bh for b
b=2A/h
Write the equation of the line that passes through the points (3, 11) and (7, 27)
y-11=4(x-3) OR y-27=4(x-7)
Solve with Elimination
8x+5y=9
2x-5y=-4
(1/2, 1)