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Zlomkové rovnice
100

3x = 11 + 1

x=?

x = 4

100

x + y = 10

x = 6 + y

y = 2

x = 8

100

9h + 21

3(3h + 7)

100

6x / 4

3x / 2

100

x / 2 = 6

x = 12

200

3x/8 + 5 = x

x = 8

200

2c = 5c − 18

d + c = −1

c = 6

d = −7

200

a² − 121

(a − 11)(a + 11)

200

(a² − 81) / (4a + 36)

(a − 9) / 4

200

x / 5 = 3

x = 15

300

3x/6 + x/6 = 2

x = 3

300

5x − 7y = 35

7(3x − 2y) = 35

x = 7

y = 0

300

k² + 4k + 1

Nemá řešení

300

(x² − 81) / (3x − 27)

(x + 9) / 3

300

x / 4 + 2 = 6

x = 16

400

12 / 5 = 18m

m = 2/15

400

(x + 2) / 7 = y / 14

x/3 + y/2 = 2

x = 2

y = 8

400

16m² + 56mn + 49

(4m + 7n)²

400

(3x² − 6x) / (12x(x − 2))

1 / 4

400

x / 3 − 2 = 4

x = 18

500

0.6f = 12

f = 20

500

x = 3y

x + 2 = 2(y + 2)

x = 6

y = 2

500

24a³b² + 52ab³

4ab²(6a² + 13b)

500

(18wz² + 24w²z²) / (9w²z² − 12wz²)

2(w + 4) / (3w − 4)

500

(3x - 2)/5 + (4x + 7)/8 - (2x - 5)/6 = (5x + 1)/10 + (x - 3)/12

x = -175/22

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