Differentiation
Integration
stuff
Area and Volume
100

f(x)= 3e2x

g(x)= x2-2x

h(x) = f(x) * g(x)

Derive h(x). Simplify

6e2x(x2-x-1)

100

f(x) = 2/(4x+7)

Antiderive f(x).

1/2 * ln|4x+7| + C

200

f(x) = 1/2 * csc(2x)

Derive f(x). Simplify

-csc(2x)cot(2x)

200

f(x) = 2e2x

Find the area under the curve from x=0 to x=1/2.

e-1

200

f(x) = (4x3-2x2+5) / (6x2-10x3-5x)

Find the limit of f(x) as x approaches infinity

-2/5

200

A circle's radius is changing at a rate of 4 m/s. Find the rate of change of the area when the radius is 2 m. 

A=pi * r2

CALCULATOR ALLOWED

16pi

300

f(x) = ln(8x5+4x3+12x2+7x+234)

find the limit of fl(x) as x approaches infinity

0

300

f(x) = cot(x/2)


Antiderive f(x).

2 ln |sin(x/2)| + C

300

The acceleration of a particle is given by the function a(t)=3t2+7. Find the position function of the particle given that its initial velocity is 10 m/sec and an initial height of 80m.

s(t)=.25t4+3.5t2+10t+80?

300

f(x) = x2-3x-10

g(x) =  -x2+5x+14

Find the area between the curves.

CALCULATOR ALLOWED

170.667

400

f(x) = arctan(4ex/2)

Derive f(x). Simplify.

(2ex/2)/(1+16ex)

400

f(x) = 4 sec(2x) dx

Find the area under the curve from x=0 to x=pi

0

400

The acceleration function for a given object is 3t2-1/3*t3. Find the total distance traveled by the object from 0 to 3.


16.2

400

Find the volume of the region bounded by y=x2, x=2, and y=0, rotated around y axis.

CALCULATOR ALLOWED

8pi

500

f(x) = x(4x+1)1/2


Derive f(x). Simplify.


(6x+1) / (4x+1)1/2

500

S   dx / (4-9x2)1/2

Integrate.


1/3 * arcsin(3x/2) + C

500

f(x) = 8x3

g(x) = sin(pi*x)

Find the volume of the shape created when revolving the area between the two curves around the line y=1, for x >= 0.

CALCULATOR ALLOWED

.208pi or .654

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