The ___________ can be used to find the missing side length in a right triangle.
Pythagorean Theorem
100
A Parallelogram with a base measure of 4ft. and a height of 6 ft.
Area = 24 square feet
100
A rectangular prism with a base area of 25ft squared and a height of 10ft.
V = 250 cubic feet
100
Factor: a^2 - 5a + 6
(a – 2) (a – 3)
100
An isosceles triangle has a a base angle measure of 40 degrees. Find the measure of the other two angles.
40 degrees and 100 degrees.
200
The sum of the areas of the individual figures (shapes) that make up the outside of a three-dimensional object.
Surface area
200
A triangle with a height of 11 inches and a base of 9 inches.
Area = 49.5 square inches
200
A cube with a height of 4 inches.
v = 64 cubic inches
200
Factor: 4x^2 + 12xy + 9y^2
(2x + 3y)^2
200
Find the length of the missing side of a right triangle if the legs are 3 in. and 4 in.
5 in.
300
________ is the longest side of a right triangle.
The hypotenuse
300
A trapezoid with a height of 6 ft and base measures of 4ft and 10ft.
Area = 42 square feet
300
A cylinder with a base diameter of 10 ft. and a height of 6 ft.
v=471 cubic ft.
300
Rewrite in slope-intercept form 3x – 2y = 4.
y = -3/2x + 2
300
Find the length of the missing side of a right triangle if the leg is 96 ft. long and the hypotenuse is 100 ft. long.
28 ft.
400
Radius is _________ the diameter.
half
400
A circle with a radius of 6.5 inches.
Area = 132.67 square inches
400
A square pyramid with a base length of 7 cm and a pyramid height of 14 cm.
v=228.6 cubic cm
400
Simplify 3(x + 2) – (x – 3)
2x + 9
400
To get from point A to point B you must avoid walking through a pond. To avoid the pond, you must walk 34 meters south and 41 meters east. How many meters would it be if it were possible to walk through the pond?
53.3 Meters
500
Set up a ____________ to compare degrees to length in order to find the arc of a circle. (When central angle is given)
Proportion
500
Find the surface area of a rectangular prism with a height of 11 ft, width of 14 ft and a depth of 9 ft.
Area = 1,386 square ft
500
A cone with a diameter of 12 cm and a height of 9.5 cm.
v=357.96 cubic cm
500
Factor 16x^2 – 144y^2
16(x – 3y) (x + 3y)
500
In a computer catalog, a computer monitor is listed as being 19 inches. This distance is the diagonal distance across the screen. If the screen measures 10 inches in height, what is the actual width of the screen to the nearest inch?